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" The area of a rectangle is equal to the product of its base and altitude. "
The Logic and Utility of Mathematics,: With the Best Methods of Instruction ... - Σελίδα 247
των Charles Davies - 1850 - 375 σελίδες
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Modern Commercial Arithmetic

Frank Joseph Schneck - 1902 - 288 σελίδες
...and three or more sides that are parallelograms, is a Prism. TRIANGULAR PRISM RECTANGULAR PRISM 212. The area of a rectangle is equal to the product of its length and breadth. 213. A rectangular prism that is one unit high has a volume equal to the product...

Elements of Plane and Solid Geometry

Alan Sanders - 1903 - 396 σελίδες
...the first rectangle is 20 sq. ft., as that has not yet been established.] PROPOSITION V. THEOREM 586. The area of a rectangle is equal to the product of its base and altitude. BC D Let ABCD be any rectangle. To Prove ABCD = axb. Proof. Let the square U, each side of which is...

Mathematics, mechanics, heat

American School (Chicago, Ill.) - 1903 - 390 σελίδες
...that is, B ~ tf Multiplying equations (1) and (2), we have A a X b B ~ a' x V THEOREM 1 XIII. 1 94. The area of a rectangle is equal to the product of its base and altitude. iL Let a and b be the numerical measures of the altitude and base of the rectangle A, and let B be...

School Algebra

John Marvin Colaw - 1903 - 444 σελίδες
...equal to the subtrahend. 58. The product divided by the multiplier is equal to the multiplicand. 59. The area of a rectangle is equal to the product of its base by its altitude. 60. The area of a circle is equal to the square of its radius multiplied by w....

First Course in Algebra

William Benjamin Fite - 1913 - 304 σελίδες
...mW + 5 mw4 + w5. 51. Multiplication of Polynomials. — The student is familiar with the fact that the area of a rectangle is equal to the product of its base and altitude. If we have two rectangles with the common altitude a and bases x and y respectively, their combined...

Schultze and Sevenoak's Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - 1913 - 490 σελίδες
...of its sides 20 in. Find the ratio of the areas of the two rectangles. PROPOSITION III. THEOREM 347. The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove B = a x b. Proof. Let U be the unit of surface....

First Course in Algebra

William Benjamin Fite - 1913 - 368 σελίδες
...m2»3 + 5 mn* + и5. 51. Multiplication of Polynomials. — The student is familiar with the fact that the area of a rectangle is equal to the product of its base and altitude. If we have two rectangles with the common altitude a and bases x and y respectively, their combined...

Solid Geometry

Walter Burton Ford, Charles Ammerman - 1913 - 184 σελίδες
...called its dimensions. In Chapter IV (§ 181), we assumed (without proof) the well-known principle that the area of a rectangle is equal to the product of its two dimensions. Similarly, we shall now assume that the volume of a rectangular parallelepiped" is...

Plane Geometry

Walter Burton Ford, Earle Raymond Hedrick - 1913 - 272 σελίδες
...THEOREM 181. Area of a Rectangle. The fundamental principle, mentioned in the Introduction (§ 25), that the area of a rectangle is equal to the product of its base by its height, will be presupposed in what follows in the present chapter. The principle states...

Elementary Algebra Revised

Frederick Howland Somerville - 1913 - 458 σελίδες
...usually with greater clearness, if general or literal number symbols are employed. To illustrate : (a) The area of a rectangle is equal to the product of its height, or altitude, by its length, or base. Or, arithmetically, Area = altitude x base. Using only...




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