| Horace Mann - 1851 - 384 σελίδες
...lines 10ft. apart. This mode of operation is founded on the property of right-angled triangles, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. A roof is said to have a true pitch, when the length of each rafter... | |
| Benjamin Greenleaf - 1851 - 332 σελίδες
...side AC the hypolhenuse, and the angle at B is a right angle. ART. 272. In every right angled triangle the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular, as shown by the following diagram. It will be seen by examining... | |
| William Smyth - 1851 - 272 σελίδες
...the other two sides ? NOTE. In solving this and other similar questions, it will be recollected that the square of the hypothenuse is equal to the sum of the squares of the other two sides, and the area is equal to one half the product of these sideS. ANS.... | |
| American Oriental Society - 1860 - 632 σελίδες
...converse process. This is simply an application of the familiar rule, that in a rightangled triangle the square of the hypothenuse is equal to the sum of the squares of the other two sides, to the triangle produced by the gnomon as perpendicular, the shadow... | |
| Frederick Overman - 1851 - 452 σελίδες
...angle from the middle of the hypothenuse is equal to half the hypothenuse. In a right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the two sides. If an angle be bisected by a right line,' which cuts the base, the segments... | |
| Edward Deering Mansfield - 1851 - 348 σελίδες
...in the year five hundred and ninety before Christ, who discovered the fundamental proposition that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Euclid appeared in the year three hundred BC His object was to systematize... | |
| Charles William Hackley - 1851 - 540 σελίδες
...and a very simple formula depending upon the well-known property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
| Jeremiah Day - 1851 - 418 σελίδες
...referred to. 94. Other relations of the sine, tangent, &c., may be derived from the proposition, that the square of the hypothenuse is equal to the sum of the squares of the perpendicular sides. (Euc. 47. 1.) In the right angled triangles CBG, CAD, and CHP,... | |
| Thomas Kentish - 1852 - 258 σελίδες
...29, and raise a perpendicular BC = 17. Join AB; apply it to the scale, and it will be found 33.6. For the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular. It is required to find the diameter of a copper, that, being... | |
| Adolfo de Castro y Rossi - 1853 - 290 σελίδες
...triangle rectangle;' " or with an Englishman who reads the same thing in his own language thus : " ' The square of the hypothenuse is equal to the sum of the squares of the two other sides of a rectangle triangle! " Thirdly, those who read in a well-known tongue,... | |
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