 | Daniel Adams - 1858 - 354 σελίδες
...obtained, together with the cube of the last quotient, to the former product for a subtrahend. VII. Subtract the subtrahend from the dividend, and to...remainder bring down the next period for a new dividend, vith which proceed as before, till the work is finished. NOTE 1 . — If it happens that the divisor... | |
 | Benjamin Greenleaf - 1858 - 472 σελίδες
...for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the product annex two ciphers for... | |
 | Elias Loomis - 1858 - 394 σελίδες
...figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
 | Thomas William Silloway - 1858 - 236 σελίδες
...the right hand of the divisor. Multiply the divisor by the last quotient-figure, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, 4th, Double the quotient already found for a partial divisor, and from these find the next figure in... | |
 | Charles Haynes Haswell - 1858 - 350 σελίδες
...period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor is contained... | |
 | Benjamin Greenleaf - 1858 - 332 σελίδες
...represent? What is the rule for extracting the cube root ? Subtract the subtrahend from the dicidend, and to the remainder bring down the next period for a new dicidend, with which proceed at before; and so on, till the whole is completed. NOTE 1. — In separating... | |
 | Benjamin Greenleaf - 1858 - 458 σελίδες
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately over it, add the square of... | |
 | Benjamin Greenleaf - 1859 - 334 σελίδες
...its contents ? What part of Fig. 4 does it represent ? What is the rule for extracting the cube root? Subtract the subtrahend from the dividend, and to...next period for a new dividend, with which proceed ai before ; and so on, till the whole is completed. NOTE 1. — In separating the given number into... | |
 | Charles Guilford Burnham - 1859 - 338 σελίδες
...the last ; under these write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to...remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? ,... | |
 | Horatio Nelson Robinson - 1859 - 352 σελίδες
...the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
