 | Joseph Ray - 1866 - 250 σελίδες
...quotient. Multiply the divisor by this term, and subtract the product from the dividend. 3. Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product... | |
 | James Hamblin Smith - 1869 - 412 σελίδες
...expression 3ab + b' we obtain the full divisor За' + За6 + b'. Hence our rule proceeds thus : " Divide the first term of the remainder by the first term of the divisor and add the result to the first term of the roof. Tlien SA 10 take three times the product... | |
 | Robert Wallace - 1870 - 164 σελίδες
...the whole divisor by this term of the quotient, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor for a second term of the quotient ; multiply as before, and subtract the product from the first... | |
 | Joseph Ray - 1866 - 420 σελίδες
...product from the remainder. 4th. Double the terms of the root already found for a partial divisor, divide the first term of the remainder by the first term of the divisor, and proceed in a similar manner to find the other terms. 1. Find the square root of 4xy-fl2afy-|-9a;2—... | |
 | William Guy Peck - 1875 - 348 σελίδες
...quotient. Multiply the divisor by this term, and subtract the product from the dividend. III. Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product... | |
 | Charles Scott Venable - 1880 - 168 σελίδες
...multiply the divisor by the first term of the quotient, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor, and proceed as before, continuing the process with the terms that remain. Ex. 1. Divide x'... | |
 | George Albert Wentworth - 1881 - 406 σελίδες
...divisor, by p, the second term of the quotient. That is, the second term of the quotient is obtained by dividing the first term of the remainder by the first term of the divisor. In like manner, the third term of the quotient is obtained by dividing the first term of the... | |
 | William James Milne - 1881 - 360 σελίδες
...term of the root, we consider z2 + 2z as one quantity, which we multiply by 2 for the trial divisor. Dividing the first term of the remainder by the first term of the divisor, the third term of the root is obtained, which is — 5. Annexing this, as before, to the trial... | |
 | James Hamblin Smith - 1883 - 466 σελίδες
...expression 3ab + 62 we obtain the full divisor 3a2 + 3ab + V. Hence our rule proceeds thus : " Divide the first term of the remainder by the first term of the divisor, and add ~the result to the first term of the root. Then take three times the product of the... | |
 | Edwin Pliny Seaver, George Augustus Walton - 1881 - 304 σελίδες
...the remainder in the same way that the terms of the dividend and divisor have been arranged. Divide the first term of the remainder by the first term of the divisor, and the result is the second term of the quotient. Multiply the divisor by this term, and... | |
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Then divide the first term of the remainder by the first term of the divisor... 
