 | William Smyth - 1858 - 344 σελίδες
...viz. Having arranged the divisor and dividend with reference to the powers of the same letter, 1°. Divide the first term of the dividend by the first term of the divisor, the result will be the first term of the quotient; 2°. multiply the whole divisor by the term of the... | |
 | John Fair Stoddard, William Downs Henkle - 1859 - 538 σελίδες
...both dividend and divisor according to the ascending or descending powers of the same letter in both. 2. Divide the first term of the dividend by the first term of the divisor ; the result will be the first term of the quotient, by which multiply all the terms in the divisor,... | |
 | Charles Davies - 1859 - 324 σελίδες
...dividend and divisor with reference to a (Art. 44), placing the divisor on the left of the dividend. Divide the first term of the dividend by the first term of the divisor ; the result will be the first term of the quotient, which, for convenience, we place under the divisor.... | |
 | Horatio Nelson Robinson - 1859 - 348 σελίδες
...hand of the dividend, as in simple numbers. II. Find the first term of the quotient either by dividing the first term of the dividend by the first term of the divisor, or by dividing the first two terms of the dividend by the first two terms of the divisor ; multiply... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...hand of the dividend, as in simple, numbers II. Find the first term of the quotient either by dividing the first term of the dividend by the first term of the divisor, or by dividing the first two terms of the dividend by the first two terms of the divisor ; multiply... | |
 | Robert Fowler - 1861 - 426 σελίδες
...both the divisor and dividend according to the powers of the same letter (a in the example) ; then to divide the first term of the dividend by the first term of the divisor, place the result in the quotient and multiply the divisor by it ; subtract and proceed similarly with... | |
 | Thomas Sherwin - 1862 - 252 σελίδες
...before; and thus continue, until all the terms of the root are found. \ Remark 2. In dividing, we merely divide the first term of the dividend by the first term of the divisor; and it is manifest, from the manner in which the divisors are obtained, as well as from inspection, that... | |
 | Isaac Todhunter - 1863 - 302 σελίδες
...ascending powers of some common letter, or both according to descending powers of some common letter. Divide the first term of the dividend by the first term of the divisor, and put the result for the first term of the quotient; multiply the whole divisor by this term and subtract... | |
 | Horatio Nelson Robinson - 1863 - 432 σελίδες
...quotient similarly arranged. We can therefore obtain this term of the quotient, by simply dividing the first term of the dividend by the first term of the divisor, thus arranged. The operation may then be continued in the manner of long division in Arithmetic ; each... | |
 | Benjamin Greenleaf - 1863 - 338 σελίδες
...terms, 3а? с -\-6abc -f- 3 V с -{- 3 a c1.-f- 3 6 c1 -f- c", for a remainder or dividend. Dividing the first term of the dividend by the first term of the trial divisor, 3а1, we obtain c, the third term of the root. Adding together three times the square... | |
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Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend. 
