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Βιβλία Βιβλία 51 - 60 από 170 για To divide by 10, 100, 1000, etc., it is necessary only to move the decimal point....
" To divide by 10, 100, 1000, etc., it is necessary only to move the decimal point in the dividend as many places to the left as there are ciphers in the divisor. "
A Complete Arithmetic, Oral and Written - Σελίδα 208
των Malcolm MacVicar - 1876 - 394 σελίδες
Πλήρης προβολή - Σχετικά με αυτό το βιβλίο

The Rudiments of Arithmetic: Embracing Mental and Written Exercises for ...

Joseph Ray - 1866 - 192 σελίδες
...ciphers in the multiplier. Thus; $12.50=1250 cents ; $2.255=2255 mills. 3. In dividing, move the point as many places to the left as there are ciphers in the divisor. Thus ; 275 cents =$2.75 ; 4255 mills = $4.255. EXAMPLES FOE PEACTICE. 1. How many dollars in 145 cents?...

The principles of arithmetic

Daniel O'Sullivan - 1872
...fraction into a simple number, we set down the numerator (by itself), and remove the decimal point as many places to the left as there are ciphers in the denominator. Thus, -3s=3-+10=-3; i§g=789-r-i00=7-89; t§io=67i ,000= -067 ; &c. XOTE. — The Fractional...

New Practical Arithmetic: In which the Science and Its Applications are ...

Henry Bartlett Maglathlin - 1873 - 336 σελίδες
...1708^-fSf. 64, "When the divisor is 10, 100, 1000, etc., the quotient may be obtained, at once, by removing the decimal point in the dividend, as many places to the left as there are ciphers in tht divisor. For, since the value denoted by figures is multiplied by 10 by re moving the decimal point...

A Complete Arithmetic: Uniting Mental and Written Exercises in a Natural ...

Emerson Elbridge White - 1870 - 340 σελίδες
...four or five decimal places. 2. To divide a decimal by 10, 100, 1000, etc., Remove the decimal point as many places to the left as there are ciphers in the divisor. REVIEW PROBLEMS. 1. Reduce Tf-j to a decimal. 2. Reduce -j:sinr *oa decimal. 3. Change .325 to a common...

The Complete Arithmetic, Μέρος 1

Daniel W. Fish - 1874
...to 4 decimal places, unless great accuracy is required. 4. To divide by 10, 100, 1000, etc., remove the decimal point in the dividend as many places to the left as there are ciphers in the divisor. (266, 3.) 8. Divide 88.476 by 1.2 ; by 3.6 ; by .Щ ; by 1.04. 9. Divide $56.05 by .59 ; $408.37£...

An Intermediate Arithmetic ...: (Robinson's Shorter Course).

Daniel W. Fish - 1874
...to 4 decimal places, unless great accuracy is required. 5. To divide by 10, 100, 1000, etc., remove the decimal point in the dividend as many places to the left as there are ciphers in the divisor (113). Find the value of 9: 75ч- .75. 10. .75 ч- 75. 11. 7.5 ч- .75. 12. 2.5 ^- 12.5. 13. .56 ч-...

The Complete Arithmetic: Oral and Written

Daniel W. Fish - 1874 - 516 σελίδες
...4 decimal places, unless great accuracy is required. 4 . To divide by 10, 100, 10(10, etc., remove the decimal point in the dividend as many places to the left as there arc ciphers in the divisor. (26O, 3.) 8. Divide 88.476 by 1.2 ; by 3.6 ; by .01£; by 1.04. 9. Divide...

The Junior-class Arithmetic: Oral and Written : Designed for Graded Schools

Daniel W. Fish - 1875 - 318 σελίδες
...to 4 decimal places, unless great accuracy is required. 5. To divide by 10, 100, 1000, etc., remove the decimal point in the dividend as many places to the left as there are ciphers in the divisor (113). Find the value of 9. 75 -f- .75. 10. .75 -r- 75. 11. 7.5 -H. 75. 12. 2.5 4- 12.5. 13. .56 —...

A Practical Business Arithmetic ...

Lorenzo Fairbanks - 1875
...may be continued. 6. A decimal may be divided by 10, 100, 1000, etc., by removing the decimal point as many places to the left as there are ciphers in the divisor. EXAMPLES FOR PRACTICE. 1. Divide .16 by .2. ' 2. Divide 32.864 by .08. 3. Divide .00.075 by .015. ,...

New Elementary Arithmetic: Embracing Mental and Written Exercises, for Beginners

Henry Bartlett Maglathlin - 1875 - 208 σελίδες
...by 10, cutting off two figures divides it by 100, etc. The Decimal Point (Art. 24), by being removed as many places to the left as there are ciphers in the divisor, may be used to denote where the cutting off is made, and the remainder will be the part on the right...




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