| Charles Davies - 1847 - 368 σελίδες
...common factor. CASE I. 128. To reduce an improper fraction to its equivalent whole or mixed number. Divide the numerator by the denominator, the quotient will be the whole number ; and the remainder, if there be one, placed over the given denominator, will form the fractional part. 127. What is reduction?... | |
| James Robinson (of Boston.) - 1847 - 304 σελίδες
...contained times in the numerator. Hence, the following rule for reducing an improper fraction to a whole or mixed number. RULE. Divide the numerator by the denominator; the quotient will be the whole or mixed number. 1. Change -tf, -tf. ¥- ¥•! 2- Change Jp, ^, H, f|, •3J1-, *B2-, and -4T9-, to... | |
| Charles Davies - 1847 - 368 σελίδες
...common factor. CASE I. 128. To reduce an improper fraction to its equivalent whole or mixed number. Divide the numerator by the denominator, the quotient will be the whole number ; and the remainder, if there be one, placed over the given denominator, will form the fractional part. 127. What is reduction?... | |
| William Vogdes - 1847 - 324 σελίδες
...mixed number reduced to an improper fraction? § G9. CASE 3. To reduce an improper fraction to ita equivalent whole or mixed number. RULE. Divide the numerator by the denominator, and the quotient will be the whole or mixed number required. EXAMPLES. I. Reduce Д^ to its mixed number.... | |
| Daniel Adams - 1848 - 342 σελίδες
...express the fractional part. Hence, To reduce an improper fraction to a whole or mixed number, KULE. Divide the numerator by the denominator ; the quotient will be 'the whole or mixed number. 6J oranges. 4 24 fourths in 6 oranges. 3 « cont'd in the fraction. 27 = ^-, Ans.... | |
| George Roberts Perkins - 1848 - 234 σελίδες
...of a fraction. Jlns. fc§S. CASE III. (44.) To reduce a fraction to an integral, or mixed quantity. RULE. Divide the numerator by the denominator, the quotient will be the integral part ; if there is a remainder, place it over the denominator for the fractional part. EXAMPLES.... | |
| George Roberts Perkins - 1849 - 346 σελίδες
...for the quotient, and 4 for a remainder. Hence 3%=7.fa. (ART. 586.) Prom which we have the following RULE. Divide the numerator by the denominator ; the quotient will be the integral part of the mixed number. The remainder being placed over the denominator of the improper... | |
| George Roberts Perkins - 1849 - 344 σελίδες
...to either of the above methods. 18. To reduce an improper fraction to a mixed number, we have this RULE. Divide the numerator by the denominator; the quotient will be the integral part of the mixed number. The remainder, placed over the denominator of the improper fraction?... | |
| Charles Davies - 1850 - 412 σελίδες
...VULGAR FRACTIONS. CASE I. 110. To reduce an improper fraction to its equivalent whole or mixed number. Divide the numerator by the denominator; the quotient will be the whole number ; and the remainder, if there be one, placed over the given denominator will form the fractional part. It was shown in Art.... | |
| George Roberts Perkins - 1850 - 356 σελίδες
...to either of the above methods. 18. To reduce an improper fraction to a mixed number, we have this RULE. Divide the numerator by the denominator; the quotient will be the integral part of the mixed number. The remainder, placed over the denominator of the improper fraction,... | |
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