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" CB, BA, by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. Then, because the angle at D is a right angle, the angle ACB is greater than a right angle ; (i. "
Euclid's Elements of plane geometry [book 1-6] explicitly enunciated, by J ... - Σελίδα 60
των Euclides - 1860
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Euclid in Paragraphs: The Elements of Euclid: Containing the First Six Books ...

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...AC, and twice the rectangle CB, BD ; that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BD. Secondly, let AD...right angle, the angle ACB is greater § than a right J ' 18.1> angle ; and therefore the square of AB is // equalIT to the squares of AC, CB, and // * 12....

Euclid's Elements of geometry [book 1-6, 11,12] with explanatory notes ...

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...AC, and twice the rectangle CB, BD ; that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BD. Secondly, let .AD fall without the triangle ABC. A Then, because the angle at D is a right angle, the angle ACB is greater than a right angle ; (i....

The Elements of Euclid, the parts read in the University of Cambridge [book ...

Euclides - 1846 - 292 σελίδες
...is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BD. Next, let AD fall without the triangle ABC : Then, because...angle, the angle ACB is greater than a right angle (1. 16) ; and therefore the square of AB is equal to the squares of AC, CB, and twice the rectangle...

Elements of Geometry: Containing the First Six Books of Euclid, with a ...

Euclid, John Playfair - 1846 - 334 σελίδες
...DA2=AC2 (47. 1.) ; therefore BC2+AB2= 2BC.BD + AC2 ; that is, AC2 is less than BC2+AB2by2BC.BD. B nc Secondly, let AD fall without the triangle ABC :*...angle at D is a right angle, the angle ACB is greater (16. 1.) than a right angle, and AB2= (12. 2.) AC2+BC2+2BC.CD. Add BC2 to each; then AB2 + BC2=A.C2-f2BC2+2BC.CD....

The first three books of Euclid's Elements of geometry, with theorems and ...

Euclid, Thomas Tate - 1849 - 120 σελίδες
...AC, and twice the rectangle CB, BD, that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, let AD fall without the triangle A ABC : Then, because the angle at D is a right angle, the angle ACB is greater (i. 16.) than a right...

The first two books of the Elements of Euclid, with additional figures ...

Euclides - 1852 - 152 σελίδες
...square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. BOOK^II. CASE II. Secondly, let AD fall without the triangle ABC: Then, because the angle at D is a right angle, 4 xvi. i. the angle ACB is greater 11 than a right angle; and therefore the square of AB is xii. 2....

The geometry, by T. S. Davies. Conic sections, by Stephen Fenwick

Royal Military Academy, Woolwich - 1853 - 400 σελίδες
...AC, and twice the rectangle CB, BD ; that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BD. Secondly, let AD...angle at D is a right angle, the angle ACB is greater (16. i.) than a right angle ; and therefore the square of AB is equal (12. n.) to the squares of AC,...

The synoptical Euclid; being the first four books of Euclid's Elements of ...

Euclides - 1853 - 146 σελίδες
...AC, and twice the rectangle CB,BD; that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BD. Secondly, let AD fall without the triangle ABC. A fl B CD Then, because the angle at D is a right angle, (I. 16.) 1. The angle ACB is greater than...

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Euclides - 1853 - 176 σελίδες
...squares of С b, ba by twice the rectangle С b, b d. Secondly, let ad fall without the triangle abС. Then, because the angle at d is a right angle, the angle a С b is greater (i. 1 6) than a right angle ; and therefore the square of ab is equal (ii. 12) to...

The geometry of the three first books of Euclid, by direct proof from ...

Euclides - 1856 - 168 σελίδες
...rectangle BC, B T>. Secondly, let AD fall without the triangle ABC (Fig. 42). Then, because the angle ADB is a right angle, the angle ACB is greater than a right angle, and therefore the square of AB (Prop. 55), is equal to the squares of AC, BC and twice the rectangle...




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