| William Tate - 1837 - 358 σελίδες
...fractions, and complex fractions being reduced to simple fractions, multiply all the numerators together for a new numerator, and all the denominators together for a new denominator. Observe, that if the same number occurs as both a numerator and a denominator, it may be cancelled... | |
| Nathan Daboll - 1837 - 262 σελίδες
...ones, and those ai dînèrent integers to the same ; then multiply all the numerators together for a new numerator, and all the denominators together for a new denominator. , EXAMPLES. 1. Multiply I by I Answers u=i 2. Multiply £ by 4 ¿fr 3. Multiply 5 1 by if 4. Multiply... | |
| Luther Ainsworth - 1837 - 298 σελίδες
...or mixed numbers to equivalent improper fractions ; then multiply all the numerators together, for a new numerator, and all the denominators together, for a new denominator, and you will have the fraction required. 1. Reduce 4 of f of } of J to a simple fraction. Operation.... | |
| Roswell Chamberlain Smith - 1841 - 324 σελίδες
...reduce them to such first, then multiply each numerator by all the denominators except its own, for a new numerator; and all the denominators together for a new denominator. 6. Reduce f , f , and 4 to a com. denominator. A -St- • '-" j - 13_ **•• 12TT». TITS'- T2f2x6x7=... | |
| John M'Nevin - 1841 - 300 σελίδες
...the following Rule is deduced: multiply each numerator by all the denominators, except its own, for a new numerator, and all the denominators together for a new denominator. Example.— Add 62£ " 37| Add 4, i, f, and TV together, (say dollars.) By Reduction $ is equal to... | |
| Thomas Sherwin - 1841 - 314 σελίδες
...we deduce the RULE FOR MULTIPLYING FRACTIONS BY FRACTIONS. Multiply all the numerators together for a new numerator, and all the denominators together for a new denominator. Remark. As the results should be reduced to the lowest terms, it is convenient to represent the operation... | |
| William Ruger - 1841 - 268 σελίδες
...mixed numbers, if there be any, to equivalent fractions ; then multiply all the numerators together for a new numerator, and all the denominators together for a new denominator, which will give the product required. EXAMPLES. 1. Multiply i by -J. iX^=|, the Answer. DEM. — It... | |
| John M'Nevin - 1841 - 300 σελίδες
...the following Rule is deduced: multiply each numerator by all the denominators, except its own, for a new numerator, and all the denominators together for a new denominator. Exampk.—Add 62^ « 37| « 19f By Reduction £ is equal to 50 cents. J " 25 « Ans. l|f = $1.81t Add... | |
| Wales Christopher Hotson - 1842 - 306 σελίδες
...transformation will be effected if each numerator be multiplied by all the denominators, except its own, for a new numerator, and all the denominators together for a new denominator. Ex. To transform - - , — ; — , and , , , so as to a-1 a+1 a2+l have a common denominator. Multiplying... | |
| Roswell Chamberlain Smith - 1842 - 320 σελίδες
...reduce them to fuch first, then multiply each numerator by all the denominators except its own, for a new numerator ; and all the denominators together for a new denominator. 6. Reduce f , f , and 4 to a com. denominator. 105. 2x6x7= 84. 5x3x7 = 105. Then£=iff. 4x6x3= 72.... | |
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