 | Daniel Adams - 1828 - 266 σελίδες
...Hence, when the extremes and the number of terms are given, '.o find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will b« the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | William Kinne - 1829 - 246 σελίδες
...term, the last term, and the number of terms being given, to find the sum of all the terms. HOLE. — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical progression is 1, the last term 21, the number... | |
 | Thomas Tucker Smiley - 1830 - 188 σελίδες
...first term ; the sum is the last term. 2. Add the first and last terms together, and multiply the sum by the number of terms ; and half the product will be the sum of all the terms. Case 2. When the first and last terms (or two extremes,) are given to find the common... | |
 | Dudley Leavitt - 1830 - 154 σελίδες
...instead of $ 353.50. 16. "If 1000 bricks lie 6 inches from each other in a straight line," &c. Solution. Multiply the sum of the extremes by the number of terms, and half of the product is the answer. 1st. In going from the pile to the first brick, and carrying that brick... | |
 | Daniel Adams - 1830 - 294 σελίδες
...) Hence, when the extremes and the number of terms are given, to find the sum of all the terms, — Multiply £ th'e sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | Daniel Adams - 1830 - 280 σελίδες
...Hence, when the extremes and the number of terms are given, to find the sum of all the terms,- — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | Nathan Daboll - 1831 - 246 σελίδες
...Tiz. the first term, last term, number of terms, common difference, and sum of the series. HULK. — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical series is 3, the last term 23, and the number... | |
 | William Kinne - 1831 - 248 σελίδες
...last term, and the number of terms being given, to find the sum of all the terms. RULE.—Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical progression is 1, the last term 21, the number... | |
 | 1831 - 210 σελίδες
...and to the product add the first jlterm, the sum is the last term. | 2. Multiply the sum of the two extremes by the ! number of terms, and half the product will be the sum .of all the terms. EXAMPLES. 1. The first term of a certain series in arithmetical number of terms 15;... | |
 | Ira Wanzer - 1831 - 408 σελίδες
...The extremes and the number of terms being given, to find the sum of all the termsofthe progression. RULE. — Multiply the sum of the extremes by the number of terms, and half of the product will be the sum of the series : Or, multiply one of those factors by half of the other,... | |
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... terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms 151, what is the sum of the series? 
