 | Nathan Daboll, David Austin Daboll - 1849 - 260 σελίδες
...increase 2 miles. • CASE lie. The first term, last term, and number of terms given, to find the sum of all the terms. • ' RULE. Multiply the sum of...number of terms, and half the product will be the answer. ' EXAMPLES. 1. A man bought 12 yards of cloth in arithmetical progression. For the first yard... | |
 | Benjamin Greenleaf - 1849 - 388 σελίδες
...the extremes be multiplied by the number of terms, the product will be double the sum of the series. RULE. — Multiply the sum of the extremes by the...of terms, and half the product will be the sum of tlie series. 5. The extremes of an arithmetical series are 3 and 45, and the number of terms 22. Required... | |
 | Benjamin Greenleaf - 1849 - 336 σελίδες
...multiplied by the number of terms, the product will be double the sum of either series. Hence, 'RuLE I. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE II. — Multiply the sum of the extremes by half the number of terms, and the product... | |
 | Rufus Putnam - 1849 - 276 σελίδες
...last term as in 'Case I. , and then multiply the sum of the extremes^ half the number of terms. Or, Multiply the sum of the extremes by the number of terms, and take 4 the product. 8. How many times does the hammer of a clock strike in 12 hours ? (1-1-12) X 12... | |
 | Benjamin Greenleaf - 1850 - 368 σελίδες
...the extremes be multiplied by the number of terms, the product will be double the sum of the series. RULE. - - Multiply the sum of the extremes by the...terms, and half the product will be the sum of the series. 5. The extremes of an arithmetical series are 3 and 45, and the number of terms 22. Required... | |
 | James Robinson - 1850 - 342 σελίδες
...series of numbers in arithmetical progression, when we have the extremes and number of terms given. • RULE. Multiply the sum of the extremes by the number of terms, and divide the product by 2, the quotient will be the sum of all the terms. 1. The extremes of* an arithmetical... | |
 | Benjamin Greenleaf - 1851 - 332 σελίδες
...multiplied by the number of terms, the product will be double the sum of either series. Hence, RDLE I. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE II. — Multiply the sum of the extremes by half the number of terms, and the product... | |
 | William Smyth - 1851 - 272 σελίδες
...To find, therefore, the sum of all the terms, when the extremes and the number of terms are given, Multiply the sum of the extremes by the number of terms, and take one-half of the product. Ex. 1. In a progression by difference, the first term is 5, the last... | |
 | Benjamin Greenleaf - 1854 - 342 σελίδες
...multiplied by the number of terms, the product will be double the sum of either series. Hence, > RULE I. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE II. — Multiply the sum of the extremes by half the number of terms, and the product... | |
 | Benjamin Greenleaf - 1857 - 336 σελίδες
...multiplied by the number of terms, the product will be double the sum of either series. Hence, RULE 1. — Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the series. Or, RULE 2. — Multiply the sum of the extremes by half the number of terms, and the product... | |
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... terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms 151, what is the sum of the series? 
