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 Βιβλία Βιβλία Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor' by the last remainder, till nothing remains, the last divisor is the common measure.* 2. Divide both of the... First Book of Arithmetic for the Use of Schools - Σελίδα 83
1842
Πλήρης προβολή - Σχετικά με αυτό το βιβλίο ## First book of arithmetic for the use of schools. [With] Key. High-school ed ...

...terms. Divide the fractions and (2) (2) (3) (2) (2) the quotients by the figures Ш=ТГА=Й=Й=ТФ= placed above them. Or, If a number be wished for that...fraction be divided, the lowest term will be obtained. Reduce ||f to its lowest terms. The denominator of the fraction being 141)240(1 greater, it is divided... ## A Practical Business Arithmetic: For Common Schools and Academies. Including ...

Whitman Peck - 1868 - 293 σελίδες
...method of finding the gcd, has been to divide the greater of two numbers by the less, and the last divisor by the last remainder, till nothing remains. The last divisor is the gcd Proceed in the same manner with the divisor thus found and another number. Ex. 2. — What is the... ## National Arithmetic: Oral and Written : for Common Schools, Academies, Etc

Joseph Ficklin - 1881 - 394 σελίδες
...greater number by the less, and the divisor by the remainder, if any, and so continue to divide the last divisor by the last remainder, till nothing remains. The last divisor is the oc D. Find the G. c. D. of the following numbers : 21. 1233 and 19180. 22. 388, 399, and 580. 23. 174,... ## Unitary Arithmetic: Embodying the First Book of Arithmetic of the Irish ...

...lowest terms at once, divide the greater term by the less, and the divisor by the remainder ; and eo on, dividing each divisor by the last remainder till nothing remains. The last divisor is the nnmber by which, if the numerator and denominator of the fraction be divided, the lowest term will... ## The Practical Teacher; with which is Incorporated the Practical ..., Τόμος 2

Joseph Hughes - 1883
...there be still a remainder, the second divisor by it, and so on, always dividing the last preceding divisor by the last remainder till nothing remains. The last divisor is the GCM (/>) 625 is \ of 5000. .'. divide by 8 and multip'y the quolient by 500x3 l6l6 + 8 = 2O2. 2O2X5OOO=I,OIO,OOO... ## The Essentials of Arithmetic, Oral and Written: For upper grades, Βιβλίο 2

Gordon Augustus Southworth - 1895 - 337 σελίδες
...be the д. с. d. required. Or, — • II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the д. с. d. If there are more than two numbers, find the д. с. d. of any two of them, and then of... ## Problems in Arithmetic: Oral and Written : for Supplementary Or Independent ...

Gordon Augustus Southworth - 1903 - 152 σελίδες
...This will be the (rCD required. Or, — II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the GCD If there are more than two numbers, find the GCD of any two of them, and then of this GCD and a... ## Key to the Southworth-Stone Arithmetics

...will be the g. с. d. required. Or, — II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the g. с. d. If there are more than two numbers, find the gcd of any two of them, and then of this gcd... ## An Exercise Book in Arithmetic, Oral and Written: For Supplementary Or ...

Gordon Augustus Southworth, John Charles Stone - 1910 - 157 σελίδες
...This will be the GGD required. Or, — II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the GOD If there are more than two numbers, find the GCD of any two of them, and then of this Q-.GD and... ## The Stone-Millis Arithmetics

...Tliis will be the GCD required. Or,— II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the GCD If there are more than two numbers, find the GCD oj any two of them, and then of this GCD and a...