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" ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is... "
The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ... - Σελίδα 81
των Robert Simson - 1804
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...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC, EHF at their centres, and BAC, EDF at their circumferences: The circumference BKC...is equal to the circumference ELF. Join BC, EF; and because the circles ABC, DEF, are equal, the straight lines drawn from their centres are equal : Therefore...

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...lines drawn from their centres are equal : Therefore the two sides BG, GC, are equal to the two EH, 'CE HF, and the angle at G is equal to the angle at H ; therefore the base BC is equal" to the base EF: And because the 84. 1. angle at A is equal to the angle at D, the...

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...drawn from their centres » 1 Def. are equal :• therefore the two sides BG, GC are equal •Hyp. to the two EH, HF; and the angle at G is equal* to * 4. 1. the angle at H; therefore the base BC is equal * to the angle at D, the segment BAC is similar...

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...are equal: (in. def. I.) therefore the two sides BG, GC, are equal to the two EH, HF, each to each : and the angle at G is equal to the angle at H ; (hyp.) therefore the base BC is equal to the base EF. (i. 4.) And because the angle at A is equal...




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