 | Euclid, John Playfair - 1846 - 334 σελίδες
...ABC, DEF are equal, the straight lines drawn from their centres are equal : therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4. 1.) to the base EF : and because the angle at A is equal to the angle at D, the... | |
 | Euclides - 1846 - 292 σελίδες
...ABC, DEF are equal, the straight lines drawn from their centres are equal : Therefore the two sides BG, GC are equal to the two EH, HF, and the angle at O is equal to the angle at H — therefore the base BC is equal to the base EF : And, because the angle... | |
 | Euclid, Thomas Tate - 1849 - 120 σελίδες
...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC' EHF at their centres, and BAC, EOF at their circumferences : The circumference BKC is equal to the circumference ELF. Join BC, EF; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: Therefore... | |
 | Royal Military Academy, Woolwich - 1853 - 400 σελίδες
...circumferences. Let ABC, DBF be equal circles, and the equal angles BGC, EHF at their centres, and BAC, EDF at their circumferences : the circumference BKC...equal to the circumference ELF. Join BC, EF : And because the circles ABC, DEF are equal (Hyp.), the straight lines drawn from their centres are equal... | |
 | Euclides - 1853 - 146 σελίδες
...circumferences. Let ABC, DEF, be equal circles, having the equal angles BGC, EHF, at their centres, aud BAC, EDF, at their circumferences : the circumference BKC is equal to the circumference ELF. A KN Join BC, EF. And because the circles ABC, DEF, are equal, the straight lines drawn from their... | |
 | Euclides - 1853 - 176 σελίδες
...circumferences. LET abc, def be equal circles, and the equal angles bgc, ehf at their centres, and bac, edf at their circumferences. The circumference bkc is equal to the circumference e1f. Join bc, ef ; and because the circles abc, def, are equal, the straight lines drawn from their... | |
 | John Playfair - 1855 - 334 σελίδες
...drawn from their centres are equal : therefore the two sides BG, GC, are equal to the two EH, EF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4. 1.) to the base EF: and because the angle at A is equal to the angle at D, the... | |
 | Euclides - 1860 - 288 σελίδες
...drawn from their centres are equal ; therefore the two sides BG and GC are equal to the two EH and HF; and the angle at G is equal to the angle at H ; therefore the base BC is equal to the base EF (I. 4) ; and because the angle at A is equal to the angle at D, the... | |
 | Robert Potts - 1860 - 380 σελίδες
...are equal : (In. def. 1.) therefore the two sides BG, GC, are equal to the two EH, HF, each to each : and the angle at G is equal to the angle at H; (hyp.) therefore the base BCis equal to the base EF. (I. 4.) And because the angle at A is equal to... | |
 | Euclides - 1864 - 448 σελίδες
...are equal : (ln. def. 1.) therefore the two sides BG, GC, are equal to the two EH, HF, each to each : and the angle at G is equal to the angle at H; (hyp.) therefore the base BCis equal to the base EF. (l. 4.) And because the angle at A is equal to... | |
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ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is... 
