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Βιβλία Βιβλία 41 - 50 από 50 για ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines....
" ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is... "
The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ... - Σελίδα 81
των Robert Simson - 1804
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1867 - 400 σελίδες
...equal ; [III. Def. 1. therefore the two sides BG, GC are equal to the two sides Elf, HF, each to each ; and the angle at G is equal to the angle at H ; [Hypothesis. therefore the base BC is equal to the base EF. [I. 4. And because the angle at A is...

Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1868 - 410 σελίδες
...equal : (III. def. 1.) therefore the two sides BG, GC, are equal to the two EH, HF, each to each : and the angle at G is equal to the angle at H; (hyp.) therefore the base BCis equal to the base EF. (I. 4.) And because the angle at A is equal to...

Pure Mathematics, Τόμος 1

1874
...1); Therefore the two sides BG, GC are equal to the two sides Triangles EH, HF, each to each; |°°^ And the angle at G is equal to the angle at H (Hyp.) ; equal in Therefore the base BC is equal to the base EF (I. 4). . And because the angle at...

The Elements of Euclid, containing the first six books, with a selection of ...

Euclides - 1874
...(III. Def. 1) ; therefore 1. The two sides BG, GC, are equal to the two EH, HF, each to each ; A , D and the angle at G is equal to the angle at H (hyp.) ; therefore 2. The oase BC is equal to the base EF (I. 4). And because the angle at A is equal...

Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1876 - 403 σελίδες
...equal : (lli. def. 1.) therefore the two sides BG, GC, are equal to the two EH, HF, each to each : and the angle at G is equal to the angle at H; (hyp.) therefore the base BCis equal to the base EF. (i. 4.) And because the angle at A is equal to...

Elements of geometry, based on Euclid, Βιβλία 1-3

Edward Atkins - 1876
...equal (III. def. 1); Therefore the two sides BG, GO are equal to the two sides EH, HP, each to each• And the angle at G is equal to the angle at H (Hyp.); Therefore the base BC is equal to the base EF (I. 4). And because the angle at A is equal to...

The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1883 - 400 σελίδες
...equal ; [III. Def. 1. therefore the two sides BG, GCa.ro equal to the two sides EH, HP, each to each ; and the angle at G is equal to the angle at H ; [Hypothesis. therefore the base BC is equal to the base EF. [I- •*• Andbecausetheangleat^4 isequalto...

Books 3-9

Euclid, Sir Thomas Little Heath, Johan Ludvig Heiberg - 1908
...equal, the radii are equal. Thus the two straight lines BG, GC are equal to the two straight lines EH, HF\ and the angle at G is equal to the angle at H ; therefore the base BC is equal to the base EF. [i. 4] And, since the angle at A is equal to the angle at D, the segment...

Euclid's Elements in Greek: Vol. I:, Βιβλία 1-4

Richard Fitzpatrick - 2005 - 296 σελίδες
...equal. So the two (straight-lines) BG, GC (are) equal to the two (straight-lines) EH, HF (respectively). And the angle at G (is) equal to the angle at H . Thus, the base BC is equal to the base EF [Prop. 1.4]. And since the angle at A is equal to the (angle)...
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The Thirteen Books of Euclid's Elements

Euclid
...equal, the radii are equal. Thus the two straight lines BG, GC are equal to the two straight lines EH, HF; and the angle at G is equal to the angle at H ; therefore the base BC is equal to the base EF. [i. 4] And, since the angle at A is equal to the angle at D, the segment...
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