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" RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. "
Arithmetic: In which the Principles of Operating by Numbers are Analytically ... - Σελίδα 277
των Daniel Adams - 1848 - 306 σελίδες
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The Tutor's Assistant: Being a Compendium of Practical Arithmetic, for the ...

Francis Walkingame - 1833 - 204 σελίδες
...— 1), and i=^nz. Case 1. The I wo extremes, and the number of terms being given, loßnd ihe sum. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the answer.* (1) How many strokes does the hammer of a clock strike in 12 hours ft (2) A man bought 17...

Arithmetic Simplified in Three Parts

Catharine Esther Beecher - 1833 - 296 σελίδες
...the following rule ; When the extremes and number of terms are given, to find the sum of the terms, Multiply the sum of the extremes by the number of terms, and divide the product by 2. 2. The first term of a series is 1, the last term 29, and the number of terms...

Adam's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1833 - 268 σελίδες
...) Hence, when the extremes and the member of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 6OS, ?nd the number of terms 151, what...

The North American Arithmetic: Part Third, for Advanced Scholars, Τόμος 3

Frederick Emerson - 1834 - 300 σελίδες
...of all the terms. PROBLEM. I. The extremes and number of terms being given, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of the terms, and half the product will be the sum of all the terms. See Theorem 4th. 1. The first term...

The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - 1835 - 210 σελίδες
...difference, and to the product add the first ,erm, the sum is fhe. last term. 2. Multiply the sum of the two extremes by the number of terms, and half the product will be the sum of all the terms. EXAHPLES. 1. The first term of a certain series in arithmetical progression is 2, the...

Daboll's Schoolmaster's Assistant: Improved and Enl. ...

Nathan Daboll - 1837 - 262 σελίδες
...of a variety of Problems } but most of them are best understood by an ces», and are her« omitted. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical series is 3, the last term 23, and the number...

Practical Mercantile Arithmetic: In which the Theory and Practice of ...

Luther Ainsworth - 1837 - 298 σελίδες
...series. Q. What is the RULE in this case ? A. Add the two extremes together, and multiply their sum by the number of terms, and half the product will be the an. swer, or sum of the scries. EXAMPLES. 1. The first term of an arithmetical series is 3, the last...

Treatise on Arithmetic, in Theory and Practice: With an Appendix, Containing ...

James Thomson (LL.D.) - 1837 - 296 σελίδες
...Answ. 243J. RULE II. The extremes and the number of terms being given, to find the sum of the series .- Multiply the sum of the extremes by the number of terms, and take half the product. Exam. 2. The first term of an equidifferent series is I , its last term 312,...

The National Arithmetic, on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1839 - 356 σελίδες
...The first term, the last term, and the number of terms given to find the sum of all the terms. EULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum. 5. The extremes of an arithmetical series are 3 and 45, and the number of terms 22. Required the sum...

The Private Instructor, Or Mathematics Simplified: Comprising Every Thing ...

Jason M. Mahan - 1839 - 312 σελίδες
...difference, and number of terms given, to find the last term, and sum of all the terms. RULE. terms) by the number of terms, and half the product will be the sum of the series. Examples. 1. Twenty-five persons bestowed charity to a poor man; the first gave him 10 cents,...




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