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" Sir," said I, after puzzling a long time over "more requiring more and less requiring less" — "will you tell me why I sometimes multiply the second and third terms together and divide by the first — and at other times multiply the first and second... "
The Universal Modern Cambist, and Foreign and Domestic Commercial Calculator - Σελίδα 111
των Ezra S. Winslow - 1872 - 252 σελίδες
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A Practical Business Arithmetic: For Common Schools and Academies. Including ...

Whitman Peck - 1868 - 304 σελίδες
...its lowest terms, or cancel any factor common to the first lerm and either the second or third. Then multiply the second and third terms together, and divide by the first. Compound Numbers must be reduced to the lowest denomination mentioned, and the first and second terms...

Walkinghame's Tutor's Assistant ... Revised, corrected, and modernized, by E ...

Francis WALKINGAME - 1868 - 154 σελίδες
...same denomination by reduction, as also the third term to whatever denomination may be convenient. Multiply the second and third terms together, and divide by the first ; the quotient will be the answer, in the same denomination as the third term. PROOF. — As the third...

Arithmetic for schools, abridged from the author's 'Familiar explanation of ...

rev. Frederick Calder - 1869 - 258 σελίδες
...„ . . nomination, therefore no . L- I ~ I ' »'. '5''. 1 i - • ( T reduction is required. I now multiply the second and third terms together, and divide by the first : the answer is £12 13s. 4rL And this fourth term and the other three terms form the following proportion...

Elementary arithmetic. [With] Answers, Βιβλίο 1

H T. Sortwell - 1873 - 176 σελίδες
...days than in 7 days, we write 48 in the second term, and 7 in the first term. We have then merely to multiply the second and third terms together, and divide by the first. This operation may sometimes be considerably curtailed by the process called cancelling, which was...

The Massachusetts Teacher and Journal of Home and School Education, Τόμος 27

1874 - 668 σελίδες
...The abstract method runs thus : As five yards is to seven yards, so is three dollars to the answer. Multiply the second and third terms together, and divide by the first term; which gives the answer, four dollars and twenty cents. These two processes need only to be thus...

The Massachusetts Teacher: A Journal of School and Home Education, Τόμος 27

1874 - 524 σελίδες
...The abstract method runs thus : As five yards is to seven yards, so is three dollars to the answer. Multiply the second and third terms together, and divide by the first term; which gives the answer, four dollars and twenty cents. These two processes need only to be thus...

Algebra Self-taught

W. P. Higgs - 1876 - 122 σελίδες
...of x, it is only necessary to divide the product of b bc and c by a ; or x = — In other words, we multiply the ££ second and third terms together, and divide by the first, to find the fourth term, or the answer. In arithmetic, too, we are told that " the mean proportional...

Arithmetic. [With] Key

Montagu H. Foster - 1881 - 182 σελίδες
...less, the quantity purchased or sold will be less, or, if greater, greater. For the Operation. — Multiply the second and third terms together, and divide by the first : the quotient will be the quantity required, in the same name as the third term : it may be reduced...

The Competitor, Τόμοι 3-4

1883 - 248 σελίδες
...quantity could I purchase for £14 Is. lO£d ? 4. Explain why, when you work a proportion sum, yon multiply the second and third terms together, and divide by the first. 5. Three persons purchased & chest of tea .containing 95 Ib. for £11 Is. 8d. The first contributed...

English Mechanic and World of Science: With which are Incorporated ..., Τόμος 34

1882 - 650 σελίδες
...one-third of 15. 2. As In. B. In. 15 : 60 : : 8 60 8)900 112J revolutions. By rule of three direct, multiply the second and third terms together, and divide by the first (more requires more, and less requires less). By the rule of three inverse, multiply the first and...




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