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" Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let AC, CF be equiangular parallelograms, having the angle BCD equal to the angle ECG ; the ratio of the parallelogram AC to the parallelogram CF,... "
Elements of Plane Geometry According to Euclid - Σελίδα 139
των Andrew Bell - 1837 - 240 σελίδες
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1883 - 428 σελίδες
...having the angle BCD equal to the angle ECO: the parallelogram AC shall have to the parallelogram CF the ratio which is compounded of the ratios of their sides. Let BC and CG be placed in a straight line ; therefore DC and CE are also in a straight line; [I. 14. complete...

Euclid Revised: Containing the Essentials of the Elements of Plane Geometry ...

Euclid - 1890 - 442 σελίδες
....-. AB : CD = LM : NO. 272 Proposition 23. THEOREM — Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let ABCD, CEFG be equiang. Os, in which AA BCD = EGG. Place them so that a pair of the lines BC, CG forming...

The Harpur Euclid: An Edition of Euclid's Elements

Edward Mann Langley, W. Seys Phillips - 1890 - 538 σελίδες
...assumed, and to demonstrate it. PROPOSITION 23. THEOREM. Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let AC, CF be equiangr. ||gms such that L BCD= L ECG ; then ||gm AC : jgm CF in the ratio compounded of...

Proceedings of the Edinburgh Mathematical Society

Edinburgh Mathematical Society - 1899 - 340 σελίδες
...(EF : GH)2 AB :CD = EF : GH EUCLID VI. 23. Mutually equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let parallelogram BE be equiangular to parallelogram CD, and let _ to prove / / / .|pBE:||-CD = (AB:AC)(AE:AD)....

Proceedings of the Edinburgh Mathematical Society, Τόμοι 18-20

Edinburgh Mathematical Society - 1900 - 410 σελίδες
...= (EF :GH)'AB :CD = EF : GH EUCLID VI. 23. Mutually equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let parallelogram BE be equiangular to parallelogram CD, and let _ __ to prove / /I ||™BE:|rOD = (AB:AC)(AE:AD)....




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