 | Roswell Chamberlain Smith - 1856 - 334 σελίδες
...greater number by the less, and that divisor by the remainder, and so on ; always dividing the last divisor by the last remainder, till nothing remains ; the last divisor is the greatest common divisor required. 17. When the last divisor is 1, the given numbers are prime to each... | |
 | Whitman Peck - 1868 - 304 σελίδες
...method of finding the gcd, has been to divide the greater of two numbers by the less, and the last divisor by the last remainder, till nothing remains. The last divisor is the gcd Proceed in the same manner with the divisor thus found and another number. Ex. 2. — What is the... | |
 | Joseph Ficklin - 1881 - 412 σελίδες
...greater number by the less, and the divisor by the remainder, if any, and so continue to divide the last divisor by the last remainder, till nothing remains. The last divisor is the oc D. Find the G. c. D. of the following numbers : 21. 1233 and 19180. 22. 388, 399, and 580. 23. 174,... | |
 | Alexander Kennedy Isbister - 1882 - 190 σελίδες
...lowest terms at once, divide the greater term by the less, and the divisor by the remainder ; and eo on, dividing each divisor by the last remainder till nothing remains. The last divisor is the nnmber by which, if the numerator and denominator of the fraction be divided, the lowest term will... | |
 | Joseph Hughes - 1883 - 568 σελίδες
...there be still a remainder, the second divisor by it, and so on, always dividing the last preceding divisor by the last remainder till nothing remains. The last divisor is the GCM (/>) 625 is \ of 5000. .'. divide by 8 and multip'y the quolient by 500x3 l6l6 + 8 = 2O2. 2O2X5OOO=I,OIO,OOO... | |
 | Gordon Augustus Southworth - 1895 - 368 σελίδες
...be the д. с. d. required. Or, — • II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the д. с. d. If there are more than two numbers, find the д. с. d. of any two of them, and then of... | |
 | Gordon Augustus Southworth - 1903 - 152 σελίδες
...This will be the (rCD required. Or, — II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the GCD If there are more than two numbers, find the GCD of any two of them, and then of this GCD and a... | |
 | Gordon Augustus Southworth - 1906 - 332 σελίδες
...will be the g. с. d. required. Or, — II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the g. с. d. If there are more than two numbers, find the gcd of any two of them, and then of this gcd... | |
 | Gordon Augustus Southworth, John Charles Stone - 1910 - 188 σελίδες
...This will be the GGD required. Or, — II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the GOD If there are more than two numbers, find the GCD of any two of them, and then of this Q-.GD and... | |
 | John Charles Stone, James Franklin Millis - 1911 - 272 σελίδες
...Tliis will be the GCD required. Or,— II. Divide the greater number by the less and the preceding divisor by the last remainder till nothing remains. The last divisor is the GCD If there are more than two numbers, find the GCD oj any two of them, and then of this GCD and a... | |
| |
Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor' by the last remainder, till nothing remains, the last divisor is the common measure.* 2. Divide both of the... 
