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 Βιβλία Βιβλία 71 - 80 από 80 για Find also the area of the triangle, formed by the chord of the segment and the two.... Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector. The Excise Officer's Manual: Being a Practical Introduction to the Business ... - Σελίδα 97
των Joseph Bateman - 1852 - 341 σελίδες
Πλήρης προβολή - Σχετικά με αυτό το βιβλίο ## Elements of Geometry and Trigonometry from the Works of A.M. Legendre ...

Charles Davies, Adrien Marie Legendre - 1885 - 512 σελίδες
...triangle AEB. Hence, we have the following RULE. — Find the area of the coiresponding sector, and also of the triangle formed by the chord of the segment and the two extreme radii of the sector; subtract tl1e latter from the former when the segment is less than a semicircle,... ## The Colliery Engineer Pocket-book of Principles Rules, Formulæ, and Tables ...

Thomas J. Foster - 1891 - 415 σελίδες
...360°. To find the area of a segment.— Find the area of the sector having the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. If the segment is greater than a semicircle, add the two areas ; if less, subtract... ## Mensuration

William Shaffer Hall - 1893 - 62 σελίδες
...the segment is less than a semicircle, subtract from the area of the sector which has the same arc, the area of the triangle formed by the chord of the segment and the radii of the sector ; if the segment is greater than a semicircle, its area is equal to the sum of... ## The Mechanical Engineer's Pocket-book: A Reference Book of Rules, Tables ...

William Kent - 1895 - 1100 σελίδες
...finit the area of a segment of a circle: Find the area of the sector which has the same arc. and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then lake the sum of these areas, if the segment is greater than a semicircle,... ## Applied Mechanics: A Treatise for the Use of Students who Have Time to Work ...

John Perry - 1897 - 678 σελίδες
...the circle. Area of a segment of a circle. — Find the area of the sector having the same arc, and the area of the triangle formed by the chord of the segment and the two radii of the sector. Take the sum or difference of these areas as the segment is greater or less than a semicircle. Otherwise,... ## Questions and Answers from the American Machinist

1900 - 403 σελίδες
...triangle AEB, Hence we have the following rule: Find the area of the corresponding sector, and also of the triangle formed by the chord of the segment and the two extreme radii of the sector; subtract the latter from the former, the remainder will be the area of... ## The Mechanical Engineer's Pocket-book: A Reference Book of Rules, Tables ...

William Kent - 1902 - 1113 σελίδες
...find the area of a segment of a circle: Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then take the sum of these areas, if the segment is greater than a semicircle,... ## American Highway Engineers' Handbook

Arthur Horace Blanchard - 1919 - 1658 σελίδες
...a segment is the difference between the area of the corresponding sector and that of the isosceles triangle formed by the chord of the segment and the two radii drawn to the extremities of the chord. A Parallelepiped is a solid whose bounding surfaces are planes... ## A treatise on practical mensuration

Anthony Nesbit - 1859 - 450 σελίδες
...segment of a circle. ETJLE I. Find the area of the sector, having the same arc as the segment ; also, find the area of the triangle formed by the chord of the segment and the radii of the sector ; then the difference of these areas, when the segment is less than a semicircle,... ## The National Engineer, Τόμος 9

1905
...of a circle. RULE FIRST. — i. Find the area of the sector having the same arc with the segment. 2. Find the area of the triangle formed by the chord of the segment and the radii of the sector. 3. Then the sum, or difference, of these areas, according as the segment is greater...