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 Βιβλία Βιβλία EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal... The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ... - Σελίδα 80
των Robert Simson - 1804
Πλήρης προβολή - Σχετικά με αυτό το βιβλίο ## The Elements of Euclid for the Use of Schools and Colleges: With Notes, an ...

Isaac Todhunter - 1880 - 400 σελίδες
...DE is common to the two triangles ADE, CDE ; the two sides AD, DE are equal to the two sides CD,DE, each to each; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; [Construction. therefore the base EA is equal to the base EC. [I. 4. But EA was... ## The Elements of geometry; or, The first six books, with the eleventh and ...

Euclides - 1881
...triangles ADE and CDE, the two sides AD and DE, are equal to the two sides CD and DE, each to each. But the angle ADE is -equal to the angle CDE, for each of them (Const.) is a right angle. Therefore the bage AE is equal (I 4) to the base fc. C. But AE was shown... ## The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1883 - 400 σελίδες
...[Construction. and DE is common to the two triangles ADE, CDE ; the two sides AD, DE are equal to the two sides CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; " [Construction. therefore the base EA is equal to the base EC. [I. 4. But EA was... ## Books 3-9

Euclid - 1908
...equal to DC, and DE is common, the two sides AD, DE are equal to the two sides CD, DE respectively ; and the angle ADE is equal to the angle CDE, for each is right ; therefore the base AE is equal to the base CE. But AE was proved equal to BE ; therefore... ## The Thirteen Books of Euclid's Elements

Euclid
...equal to DC, and DE is common, the two sides AD, DE are equal to the two sides CD, DE respectively ; and the angle ADE is equal to the angle CDE, for each is right ; therefore the base AE is equal to the base CE. But AE was proved equal to BE ; therefore...
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