| Bourdon (M., Louis Pierre Marie) - 1839 - 368 σελίδες
...to which we bring down the two next figures 84. The result of this operation 1184, contains tzeice the product of the tens by the units plus the square of the units. But since tens multi. plied by units cannot give a product of a less name than tens, it follows that... | |
| Thomas Sherwin - 1841 - 320 σελίδες
...625. When, therefore, a number contains tens and units, its sccnnd power will contain the second power of the tens, plus twice, the product of the tens by the units, plus the second power of the units. Now let us reverse the process, and see by what means the root could be... | |
| Charles Davies - 1842 - 284 σελίδες
...(a+6)2=(64)2; or a2 + Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1,2, 3, 4, &c, tens, or units of the second order, by annexing to each... | |
| Charles Davies - 1842 - 368 σελίδες
...and (a+i) 3 =(64) 3 , Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of ihe units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by annexing to each figure a cipher,... | |
| Charles DAVIES (LL.D.) - 1843 - 348 σελίδες
...of the square AE, the two rectangles FE and EC, and the square ED : Hence The square of two figures is equal to the square of the tens, plus twice the product of the lens by the units, plus the square of the units. Let it now be required to extract the square root... | |
| Charles Davies - 1844 - 356 σελίδες
...of the square AE, the two rectangles FE and EC, and the square ED : Hence The square of two figures is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. • Let it now be required to extract the square i^oi of 1296. Since the number contains more than... | |
| Pliny Earle Chase - 1844 - 246 σελίδες
...the 7 in the root, and also at the right of the divisor, we multiply by 7, and obtain 469, which is twice the product of the tens by the units plus the square of the units. Hence we deduce the following RULE. Separate the number into periods of two figures each, by placing... | |
| Davis Wasgatt Clark - 1844 - 394 σελίδες
...24000 + 3000+ 125=91 125 283. On inspecting the above examples, it will be perceived that the cube of a number composed of tens and units is equal to the cube of the tens, plus three times the product of the square of the tens by the units, plus three times... | |
| Francis Henney Smith - 1845 - 300 σελίδες
...for any other number, we conclude, that the square of a number composed of tens and units contains the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. Q. Of what parts may every number be considered as composed ? What does 16 contain 1 251 59? 125 ?... | |
| Charles Davies - 1845 - 382 σελίδες
...(60)2 + 2 X 60 X 4 + (4)2 = 4096. Hence, the square of a number composed of tens and units contains, the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by annexing to each a cipher, we shall have,... | |
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