 | John Playfair - 1819 - 354 σελίδες
...straight lines from a point F within the figure to each of its angles. And, by the preceding proposition, all the angles of these triangles are equal to twice as many right angles as there are triangles, that is, as there are sides of the figure ; and the same angles are equal to the... | |
 | John Playfair - 1819 - 350 σελίδες
...to all the angles of the figure, together with four right angles, that is, the angles of the figure are equal to twice as many right angles as the figure has sides, wanting four. COR. 2. All the exterior angles of any rectilineal figure are tegether equal to four... | |
 | Rev. John Allen - 1822 - 516 σελίδες
...at A are greater than twice as many right angles, except four, as the figure has sides ; and all thc angles of these triangles are equal to twice as many right angles as the figure has sides (32. 1 &'«.), therefore the angles of these triangles which are at their common vertex A, being those... | |
 | Euclid - 1822 - 222 σελίδες
...equal (i)Prop. 13. to two right angles (1), therefore all the external angles, with all the internal, are equal to twice as many right angles as the figure has sides ; but the internal angles, together with four right angles, are equal to twice as many rightangles... | |
 | Charles Hutton - 1822 - 616 σελίδες
...triangles, is equal to two right angles (th. 17) ; therefore the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles about the point p, which are so / many of the angles of the triangles,... | |
 | Edward Riddle - 1824 - 572 σελίδες
...twice as many right angles as the figure has sides ; or the interior angles of the figure, themselves, are equal to twice as many right angles as the figure has sides, wanting four right angles. QED Cor. 1. All the interior angles of any quadrilateral figure are together... | |
 | Peter Nicholson - 1825 - 1046 σελίδες
...straight lines from a point F within the figure to each of its angles. And, by the preceding proposition all the angles of these triangles are equal to twice as many right angles as there are triangles, that is, as there are sides of the figure, and the same angles are equal to the... | |
 | George Lees - 1826 - 266 σελίδες
...straight lines from a point F within the figure to each of its angles. And, by the preceding theorem, all the angles of these triangles are equal to twice as many right angles as there are triangles, that is, as there are sides of the figure ; and the same angles are equal to the... | |
 | Robert Simson - 1827 - 546 σελίδες
...straight lines from a point F, within the figure to each of its angles. And, by the preceding proposition, all the angles of these triangles are equal to twice as many right angles as there are triangles, that is, as there are sides of the figure : and the same angles are equal to the... | |
 | John Radford Young - 1827 - 246 σελίδες
...in each triangle amounts to two right angles, therefore the angles of all the triangles are together equal to twice as many right angles as the figure has sides, that is to say, the sum of the angles of the polygon, together with those about the point within it,... | |
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... figure, together with four right angles, are equal to twice as many right angles as the figure has be divided into as many triangles as the figure has sides, by drawing straight lines from a point F within the figure to each of its angles. 
