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" Multiply the numerators together for a new numerator, and the denominators together for a new denominator. "
The National Arithmetic on the Inductive System: Combining the Analytic and ... - Σελίδα 168
των Benjamin Greenleaf - 1857 - 444 σελίδες
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Rational arithmetic

Sarah Porter - 1852 - 286 σελίδες
...xr, and you would proceed exactly as you did at first ; rule, — multiply the numerators together for a new numerator, and the denominators together for a new denominator. Whether the expression be two fractions, thus, - x Q = 7 - 5, or three fractions, thus, - x „ x i...

Indroduction to the National Arithmetic ...

Benjamin Greenleaf - 1854 - 342 σελίδες
...the same as reducing compound fractions to simple ones. RULE I. — Multiply the numerators together for a new numerator, and the denominators together for a new denominator; then reduce the fraction to its lowest terms. Or, RULE II. — Cancel all the common factors in the...

Smith's Inductive Arithmetic and Federal Calculator on a New, Interesting ...

Roswell Chamberlain Smith - 1855 - 154 σελίδες
...does 9 times 1 equal ? A. 1}. 2. To multiply one fraction by another, multiply the numerators together for a new numerator, and the denominators together for a new denominator. 11. A merchant had ^ of a yard of cloth in one remnant. and in another only \ as much ; what part of...

New University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - 1856 - 450 σελίδες
...(Art. 114). H^nce, to multiply one fraction by another, RULE. — Multiply the numerators together for a new numerator, and the denominators together for a new denominator. NOTES. — 1. When the multiplier is less than 1, we do not take the whole of the multiplicand, but...

Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - 1856 - 334 σελίδες
...hours. CASE v. To reduce a compound fraction to a simple one. RULE. 1. Multiply the numerators together for a new numerator, and the denominators together for a new denominator. CASE III. Q. How is a mixed number reduced to an improper fraction? 1. Why add in the numerator? 2....

Practical Arithmetic, by Induction and Analysis

Joseph Ray - 1857 - 348 σελίδες
...Reduce g of | to a simple fraction. Ans. jjj. Eule for Case IV. — Multiply the nvmerators together for a new numerator, and the denominators together for a new denominator. If mixed numbers occur, reduce them to improper fractions. 4. Reduce £ of § of 2| to a simple fraction....

The National Arithmetic on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1858 - 456 σελίδες
...the numerators, (4 -j- 5) X 3 27 Product of the denominators, 4x5 ~ 20 ~ ** By multiplying the sum of the denominators by one of the numerators for a...and the denominators together for a new denominator, we reduce the fractionrto a common denominator, and add their numerators, and thus obtain |^ = 1^,...

The National Arithmetic on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1858 - 458 σελίδες
...-j- 5) X 3 27 Product of the denominators, 4x5 SO ' "* By multiplying the sum of the denominators hy one of the numerators for a new numerator, and the denominators together for a new denominator, we reduce the fractions to a common denominator, and add their numerators, and thus obtain |J = 1^,...

The National Arithmetic on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1858 - 472 σελίδες
...the J- X % = f & Ans. multiplicand, \. Now, to obtain -| of -J-, we multiply the numerators together for a new numerator, and the denominators together for a new denominator (Art. 22G). Therefore, Multiplying one fraction by another is the same as reducing compound fractions...

The University Algebra ...

John Fair Stoddard, William Downs Henkle - 1859 - 538 σελίδες
...(16O.) To find the product of two or more algebraic fractions. RULE. Multiply the numerators together for a new numerator, and the denominators together for a new denominator. DEMONSTRATION. , -A- , C Let -=r and -=- represent any two fractious. •1 C AC We are here to prove...




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