 | John Bonnycastle - 1851 - 288 σελίδες
...divide the number 40 into two such parts, that the sum of their squares shall be 818. Ans. 23 and 17. 3. It is required to divide the number 24 into two...equal to 35 times their difference. Ans. 10 and 14. 2. To'find a number such, that if you subtract it from 10, and then multiply the remainder by the number... | |
 | Joseph Ray - 1852 - 408 σελίδες
...from 10, and multiply the remainder by the number itself, the product shall be 21. " Ans. 7 or 3. 8. It is required to divide the number 24 into two such...equal to 35 times their difference. Ans. 10 and 14. 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2... | |
 | Joseph Ray - 1848 - 250 σελίδες
...of the symbol generally give both values of the unknown quantity, as in the following question. 4. Divide the number 24 into two such parts, that their product shall be 95. Let x= one of the parts ; then 24— x= the other. And x(24— x)=95 Or £'— 24x=— 95 Whence... | |
 | 1853 - 380 σελίδες
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that theirv product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers... | |
 | Popular educator - 1854 - 922 σελίδες
...horse worth three times the 1st : what were the values of the two horses. Ans. £6, and £9. Prob. 25. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
 | 1855 - 424 σελίδες
...are thoie, whose difference, sum and product, are as the numbers 2, 3 and 6, respectively ? Prob. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares as 3 to 10. Prob. 13. In a mixture of rum and brandy, the difference between... | |
 | Charles Davies - 1856 - 224 σελίδες
...whence, by the rule, x = 50 ± VT96"= 50 ± 14 ; hence, ж = 64, x — 36, and у = 36, у = 64. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Let x and у denote the parts. From the conditions of the... | |
 | Charles Davies - 1859 - 324 σελίδες
...13. Divide 100 into two such parts, that the sum of theii square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14 15. The stun of two numbers is 8, and the... | |
 | James B. Dodd - 1859 - 368 σελίδες
...infinitely gfeat, to fulfil the conditions of the problem. - The problem is therefore impossible. EXAMPLE V. To divide the number 24 into two such parts, that their product shall be 150. If x represent one of the two parts, 24— z will represent the other and the equation will be... | |
 | Charles Davies - 1860 - 412 σελίδες
...10. Divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 12. What two numbers are they, whose product... | |
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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 
