 | Charles Davies - 1861 - 322 σελίδες
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
 | Horatio Nelson Robinson - 1861 - 372 σελίδες
...| of yours, I can purchase the house. How much money had each of them? Ana. A had $160. B $120. 12. It is required to divide the number 24 into two such parts, mat the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
 | Charles Davies - 1864 - 316 σελίδες
...Divide 100 into two such parts, that the sum of their Hquare roots may be 14. Ans. 64 and 36. 14. It i» required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
 | Joseph Ray - 1852 - 422 σελίδες
...from 10, and multiply the remainder by the number itself, the product shall be 21. Ares. 7 or 3. 8. It is required to divide the number 24 into two such...equal to 35 times their difference. Ans. 10 and 14. 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2... | |
 | Horatio Nelson Robinson - 1866 - 328 σελίδες
...two such parts, that the sum of the squares of those parts shall be b. Ans. £(a ± V26— a2). 4. It is required to divide, the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
 | Joseph Ray - 1866 - 420 σελίδες
...10, and multiply the remainder by the number itself, the product shall be 21. Ans. Y or 3. 8. Divide 24 into two such parts that their product shall be...equal to 35 times their difference. Ans. 10 and 14. 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2... | |
 | Horatio Nelson Robinson - 1874 - 340 σελίδες
...two such parts, that the sum of the squares of those parts shall be b. Am. £(a± v^¿) — a2). 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
 | Charles Davies - 1879 - 288 σελίδες
...2304. whence, by the rule, ж = 50±уТ96~=50 ± 14; hence, x = 64, x = 36, and у = 36, у = 64. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Let x and у denote the parts. From the conditions of the... | |
 | Edward Brooks - 1888 - 344 σελίδες
...The difference of two numbers is 6, and their product is 8-1; required the numbers. An». 12; 7. 6. Divide the number 24 into two such parts that their product shall be 140. Ans. 14; 10. 7. The difference of two numbers is 4 and the sum of their •quares is 208 ; what... | |
 | Edward Brooks - 1901 - 248 σελίδες
...6. The difference of two numbers is 5, and their product is 84 ; required the numbers. Am. 12; 7. 6. Divide the number 24 into two such parts that their product shall be 140. Ans. 14; 10. 7. The difference of two numbers is 4 and the sum of their •quares is 208 ; what... | |
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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 
