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" Subtract the cube thus found from the said period, and to the remainder bring down the next period, and call this the dividend. "
Practical and Mental Arithmetic: On a New Plan, in which Mental Arithmetic ... - Σελίδα 236
των Roswell Chamberlain Smith - 1833 - 268 σελίδες
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Arithmetic: In which the Principles of Operating by Numbers are Analytically ...

Daniel Adams - 1848 - 324 σελίδες
...in the root. II. Find the greatest complete cube number in the left hand period, and place its cube root in the quotient. III. Subtract the cube thus found from the period taken, and bring down to the remainder the next period for a dividend. IV. Calling the quotient,...

Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ...

Nathan Daboll, David Austin Daboll - 1849 - 260 σελίδες
...towards the right in the same manner. ' II. Find the greatest cube in the left hand period, and put its root in the quotient. III. Subtract the cube thus...period, and to the remainder bring down the next period, calling this the dividend. V. Seek how often the divisor may be had in the dividend, and place the...

Arithmetic on the Productive System: Accompanied by a Key and ..., Τόμος 1

Roswell Chamberlain Smith - 1850 - 314 σελίδες
...square in the last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient} for a partial divisor, and on its right, place, for...

Practical and Mental Arithmetic on a New Plan

Roswell Chamberlain Smith - 1852 - 298 σελίδες
...greatest cnbe in the left-hand period, and place its root in the qnotient. Snbtract the cnbe thns fonnd from the said period, and to the remainder bring down the next period, and call this the dividend. Mnltiply the sqnare of the qnotient by 300, calling it th» divisor. Find how many times the divisor...

An Introduction to Arithmetic: Containing the Most Useful Rules in Common ...

James Gray - 1854 - 120 σελίδες
...and place the root of that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide...

The tutor's assistant

Francis Walkingame - 1855 - 186 σελίδες
...the first period, and tho root thereof in the quotient ¡ subtract the square number from the first period, and to the remainder bring down the next period, and call that the resol vend. 3. Double the quotient, and place it for a divisor on the left-hand of the resolvend...

Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - 1856 - 334 σελίδες
...square in the last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for...

Adams's Improved Arithmetic: Arithmetic, in which are Combined the Analytic ...

Daniel Adams - 1861 - 452 σελίδες
...period should contain but a single figure. II. Find the greatest cube in the left-hand period, and place its root in the quotient. III. Subtract the cube thus found from the period taken, and to the remainder bring down the next period for a dividend. IV. Calling the quotient,...

Walkinghame's [sic] Tutor's assistant; or, Complete arithmetical question ...

Francis Walkingame - 1865 - 222 σελίδες
...number under the first period, and the root in the quotient ; subtract the square number from the first period, and to the remainder bring down the next period, and call that the resolvend. Thirdly, Double the quotient, and place it for a divisor on the left hand of the...

An introduction to arithmetic

James Gray - 1883 - 154 σελίδες
...and place the root of that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide...




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