 Hence it follows, we must always point off in the product as many places for decimals as there are decimal places in both factors. 2. Multiply '75 by '25. OPERATION. In this example, we have 4 de'75 cimal places in both factors ; we '25 must therefore...  Putnam's Arithmetic - Σελίδα 29των Rufus Putnam - 1849 - 264 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Thomas Kimber - 1865 - 302 σελίδες
...9900 у = 2433 _ 2433 У ~ 9900which, put in the following form, MULTIPLICATION OF DECIMALS. 90. Bule. Multiply as in whole numbers, and point off in the product as many decimal places as there are in both the multiplier and multiplicand ; if there are not figures enough,... | |
 | John Fair Stoddard - 1868 - 356 σελίδες
...SOLUTION 2a— 74.23=*^, and .012=TJ4j. Hence, 74.23 x .012=^1^ x TH*=TmsiF—89076. .89076 Rule. — Multiply as in whole numbers, and point off in the product as many decimal places as there are decimal places in the two factors. REMARK.— If necessary, prefix ciphers... | |
 | William Harding Girdlestone - 1867 - 368 σελίδες
...deduce the following practical rule for the multiplication of decimals : Multiply the decimals together as in whole numbers ; and point off in the product as many decimal places as there are in the multiplier and multiplicand together ; prefixing ciphers, if necessary,... | |
 | Francis Young (F.R.G.S.) - 1872 - 204 σελίδες
...+ 37 kilom. 6 met. 25 centim. — 9 kilom. 3 met. 75 centim. MULTIPLICATION OF DECIMALS. RULE. — Multiply as in whole numbers, and point off in the product as many decimal places as there are in the multiplier and multiplicand together. Exs. 1, 2. —Multiply 87.7... | |
 | Manual - 1873 - 168 σελίδες
...subtract as in whole numbers, not forgetting that ten tenths make a unit. Eule for multiplication : — Multiply as in whole numbers, and point off in the product as many decimal places as there are decimals in both factors. Hence the — Eule for division : — Divide... | |
 | Milton Browning Goff - 1876 - 462 σελίδες
...the multiplier under the multiplicand. Multiply as in whole numbers, and point off from the right of the product as many places for decimals as there are decimal places in the factors. If there are not enough places in the product, make a sufficient number by prefixing ciphers.... | |
 | James E. Ryan - 1877 - 212 σελίδες
...point off as in addition of decimals. (Art. 137.) 135. To MULTIPLY WHEN EITHER OR BOTH FACTORS ARE DECIMALS. Multiply as in whole numbers, and point off in the product as many decimal figures as there are in both factors, prefixing ciphers if necessary. (Problems, Art. 137.)... | |
 | George Dallas Lind - 1882 - 544 σελίδες
...pupil will have no trouble. In multiplication, the only difficulty is in giving a reason for pointing off in the product as many places for decimals as there are in both multiplicand and multiplier. This, however, is very simple, because at the beginning of this... | |
 | Charles Scott Venable - 1888 - 402 σελίδες
...tenths, 8 decimal places (the sum of 2 and 1) represent thousandths, the denominator of the answer. 495. Rule for Multiplication of Decimals. — Multiply...whole numbers and point off in the product as many decimal places as there are in the multiplicand and the multiplier together. 496. Find the products... | |
 | George Soulé - 1888 - 568 σελίδες
...EipUauUian. — In all problems of this kind, we multiply as in whole numbers, ami point ott'on the right of the product as many places for decimals as there are decimal places in both the multiplicand and multiplier. The reason ftft thus pointing oft' the 3 decimal places in this problem... | |
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