 | Benjamin Greenleaf - 1858 - 456 σελίδες
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,... | |
 | Charles Haynes Haswell - 1858 - 350 σελίδες
...left-hand period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor... | |
 | Horatio Nelson Robinson - 1859 - 362 σελίδες
...and write its root for the first figure in the required root; subtract the cube from the left hand period, and to the remainder bring down the next period for a/ dividend. III. At the, left of the dividend write three times the square of the first fyurc of the root, and... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...and write its root for the first figure in the required root; subtract, the cube from the left hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of tlie first figure of the root, and-... | |
 | Daniel Adams - 1861 - 452 σελίδες
...period, and write its root as a quotient in division. Subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | Benjamin Greenleaf - 1861 - 338 σελίδες
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. RULE. — Separate the given number into as many periods as possible of three figures each, by placing... | |
 | John Flint (inspector of schools.) - 1862 - 152 σελίδες
...period, and write its cube root as the first figure of the root. Subtract its cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the dividend... | |
 | Benjamin Greenleaf - 1863 - 338 σελίδες
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. At the left of the dividend write three times the square ofth* root already found, for a trial divisor... | |
 | Horatio Nelson Robinson - 1863 - 432 σελίδες
...wríte its root for the first figure in the root sought ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write twice the first figure, of the root, for a trial divisor ; divide... | |
 | George Augustus Walton - 1864 - 364 σελίδες
...hand period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained in the dividend... 
