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" ... subtract it therefrom, and to the remainder bring down the next period for a dividend. " Place the double of the root already found, on the left hand of the dividend for a divisor. Seek how often the divisor is contained... "
The Scholar's Arithmetic: Or, Federal Accountant : The Whole in a Form and ... - Σελίδα 134
των Daniel Adams - 1820 - 224 σελίδες
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The Computist's Manual of Facts: And Merchant's and Mechanic's Calculator ...

Ezra S. Winslow - 1853 - 264 σελίδες
...now stands, by the figure last placed in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by 2, as before, and take the product...

An Introduction to Arithmetic: Containing the Most Useful Rules in Common ...

James Gray - 1854 - 120 σελίδες
...that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide the dividend...

Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - 1856 - 334 σελίδες
...on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,...

A New System of Arithmetic, on an Improved Plan, Embracing the Rules of ...

Charles Guilford Burnham - 1857 - 342 σελίδες
...lefthand period, and place it as a, quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the...

Burnham's Arithmetic, Revised: A New System of Arithmetic, on an Improved ...

Charles Guilford Burnham - 1857 - 328 σελίδες
...lefthand period, and place it as a quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see how often the divisor is contained in the dividend,...

Practical Arithmetic, by Induction and Analysis

Joseph Ray - 1857 - 348 σελίδες
...and place its root on the right. as in division. Subtract the cube of the root from the left period, and' to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial, divisor. Find how many times this divisor...

The National Arithmetic on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1857 - 452 σελίδες
...period, and write its root as the first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor,...

Introduction to The National Arithmetic: On the Inductive System : Combining ...

Benjamin Greenleaf - 1857 - 336 σελίδες
...left-hand period, and place its root on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend, and...

The National Arithmetic on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - 1858 - 456 σελίδες
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,...

Introduction to The National Arithmetic: On the Inductive System Combining ...

Benjamin Greenleaf - 1858 - 332 σελίδες
...left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and...




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