 | Benjamin Greenleaf - 1864 - 394 σελίδες
...left-hand period, and place its root on the right ; subtract the square of this root from the first period, and to the remainder bring down the next period for a dividend. Divide this quantity, omitting the last figure, by double the part of the root already found, and annex... | |
 | George Augustus Walton - 1864 - 348 σελίδες
...period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
 | Joseph Ray - 1866 - 240 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times the divisor... | |
 | Joseph Ray - 1866 - 240 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times the divisor... | |
 | Joseph Ray - 1852 - 396 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. Srd. Double the root already found, and place it on the left for a divisor. Find how many times the... | |
 | Horatio Nelson Robinson - 1866 - 312 σελίδες
...for the first figure in the required root ; subtract the square of this figure from the first period, and to the remainder bring down the -next period for a dividend. III. Double the root already found, and write the result on the left for a divisor ; find how many... | |
 | Robert Thomson (of Southampton.) - 1866 - 143 σελίδες
...number : cube this figure placed in the quotient and place its product under the first period, subtract and to the remainder bring down the next period for a dividend. Example 1st. — Extract the cube or third root of 312908547060. 6x6=36 6x3=18x6= 10800 187x7= 1309... | |
 | Joseph Ray - 1866 - 406 σελίδες
...and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
 | Ezra S. Winslow - 1867 - 220 σελίδες
...divisor, thus increased, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting of two figures) — by 2, as before,... | |
 | Joseph Ray - 1857 - 320 σελίδες
...root on the right, like a quotient in division. Subtract the square of this root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root found, and place it on the left for a trial divisor. Find how many times the divisor... | |
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Find the greatest square number in the first or left hand period, place the root of it at the right hand of the given number, (after the manner of a quotient in division... 
