 | Ezra S. Winslow - 1853 - 252 σελίδες
...now stands, by the figure last placed in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by 2, as before, and take the product... | |
 | Benjamin Greenleaf - 1854
...in division, for the first figure of the root, and the square number under the period, subtracting it therefrom ; and to the remainder bring down the...Place the double of the root already found on the left hand of the dividend for a divisor, 4. Find how often the divisor is contained in the dividend, omitting... | |
 | James Gray - 1854 - 108 σελίδες
...that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide the dividend... | |
 | Roswell Chamberlain Smith - 1856 - 311 σελίδες
...on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,... | |
 | Charles Guilford Burnham - 1857
...lefthand period, and place it as a, quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the... | |
 | CHARLES G. BURNHAM - 1857
...lefthand period, and place it as a quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see how often the divisor is contained in the dividend,... | |
 | Joseph Ray - 1857 - 336 σελίδες
...and place its root on the right. as in division. Subtract the cube of the root from the left period, and' to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial, divisor. Find how many times this divisor... | |
 | Benjamin Greenleaf - 1857 - 324 σελίδες
...left-hand period, and place its root on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend, and... | |
 | Benjamin Greenleaf - 1857 - 444 σελίδες
...period, and write its root as the first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor,... | |
 | Benjamin Greenleaf - 1858 - 324 σελίδες
...left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and... | |
| |
Find the greatest square number in the first or left hand period, place the root of it at the right hand of the given number, (after the manner of a quotient in division... 
