 | Robert Wallace - 1870 - 164 σελίδες
...of the partial divisor. Multiply the complete divisor by the last figure of the root thus obtained, subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. Double the whole root already found for a partial divisor, and continue the operation, as before, until... | |
 | Joseph Ray - 1866 - 420 σελίδες
...and also on the right of the divifor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend,...remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Shelton Palmer Sanford - 1872 - 404 σελίδες
...the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the dividend,...remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE, 5625(75 An, 49 145)725 725 continue tlie... | |
 | Ezra S. Winslow - 1872 - 256 σελίδες
...right of the divisor ; multiply the divisor, thus increase^, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting of two figures) — by... | |
 | Henry Beadman Bryant, Emerson Elbridge White, Corydon Giles Stowell - 1872 - 576 σελίδες
...of the last root figure, and find their sum, calling it the subtraliend. 7. Subtract the subtrahend from the dividend, and to the re•mainder bring down the next period for a new dividend, ivilh which proceed as before till the required root be found. NOTES. — 1. When any dividend is not... | |
 | Horatio Nelson Robinson - 1872 - 436 σελίδες
...and the result will be the complete diiàsor. V. Multiply tlie complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder briny down another period for a new dividend. YI. Add together the last complete divisor, the last... | |
 | Elias Loomis - 1873 - 396 σελίδες
...Multiply the divisor thus increased by the last figure of the root ; subtract the product from Hie dividend, and to the remainder bring down the next period for a new dividend. 6th. Take three hundred times the square of the whole root now found for a new trial divisor, and by... | |
 | Horatio Nelson Robinson - 1874 - 340 σελίδες
...and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
 | Charles Davies - 1874 - 346 σελίδες
...root and also annex it to the divisor. IV. Multiply the divisor thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down (he next period for a new dividend. "V. Double the whole root thus found, for a new trial divisor,... | |
 | Horatio Nelson Robinson - 1875 - 430 σελίδες
...root to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend,...remainder bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor, with which... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
