 AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle...  Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Σελίδα 13των Dennis M'Curdy - 1846 - 138 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Euclid - 1810 - 554 σελίδες
...and join DC; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each; and the angle DBC is equal to the angle ACB; therefore the base DC is equal to the base AB, and the triangle... | |
 | Euclides - 1816 - 588 σελίδες
...be the greater ; and from it cut" • 3. 1. off DB equal to AC, the less, and join DC; therefore, , because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the twosides, DB, BC are equal to the two AC, CB each to each ; and the angle DBC is... | |
 | John Playfair - 1819 - 350 σελίδες
...join DC ; therefore, be- cause in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC is also equal to the angle ACB ; therefore the base DC is equal to the base AB,... | |
 | John Playfair - 1819 - 354 σελίδες
...greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, be- * cause in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC... | |
 | Adrien Marie Legendre - 1822 - 394 σελίδες
...are not equal, let AB be the greater. Take BD=AC, and join DC. The angle DBC is (Hyp.) equal to ACB ; the two sides DB, BC, are equal to the two AC, CB, by construction ; therefore (Prop. 6.), the B triangle DEC must be equal to ACB. But the part cannot... | |
 | Peter Nicholson - 1825 - 1046 σελίδες
...Let AB be the greater; and from it cut (3. 1.) off DB equal AC, the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both the two sides, DB,BC, are equal to the two AC, CB each to each ; and the angle DBC is... | |
 | Robert Simson - 1827 - 546 σελίδες
...AB be the greater ; and * 3. 1. from it cut * off DB equal to AC, the less, and join DC : therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides, DB, BC are equal to the two AC, CB, each to ' 4. 1. each; and the angle... | |
 | George Gordon Byron Baron Byron - 1831 - 498 σελίδες
...proposition of Euclid : *« Because, in the triangles DBC.ACB, DB is equal to AC, and BC, common to both; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC Is equal to the angle ACB : thereThough « Madoc," with " Pucelle */' instead of Punch, May... | |
 | George Gordon Byron Baron Byron, Thomas Moore - 1832 - 394 σελίδες
...wonder how the devil he came there." The trio are well defined in the sixth proposition of Euclid : " Because, in the triangles DBC, ACB, DB is equal to AC, and BC common to both ; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC... | |
 | George Gordon Byron Baron Byron, Thomas Moore - 1832 - 384 σελίδες
...wonder how the devil In. came there." The trio are well defined in the sixth proposition of Euclid : " Because, in the triangles DBC, ACB, DB is equal to AC, and BC common to both ; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC... | |
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