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AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle...
Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Σελίδα 13
των Dennis M'Curdy - 1846 - 138 σελίδες
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## The Elements of Euclid; viz. the first six books,together with the eleventh ...

Euclides - 1841 - 351 σελίδες
...AC. For, if AB be not equal to AC, one of them is greater than the other; let AB be the greater, and sides DB, BC are equal to the two AC, CB, each to each; and the angle DBC is equal to the angle ACB; therefore the base DC is equal to the base AB, and the triangle...

## The Complete Works of Lord Byron: Reprinted from the Last London Edition ...

George Gordon Byron Baron Byron - 1841 - 935 σελίδες
...triangles DUC, A С В, Г) В ¡я equal to Л С, and В С common to both ; the two sides l> m, В С, chin guides. XIX. White is the glassy deck, withou angle ПВС is «qua! to the angle А С В : therefore, the base О С is eqoaJ to the base AB, and...

## Chambers's information for the people, ed. by W. and R. Chambers, Τόμος 2

Chambers W. and R., ltd - 1842
...other. Let AB be the greater, and from it cut off DB equal to AC, the less, and join DC, therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both ; the two aides DB, BC, ore equal to the two AC, CB, each to each ; but the angle DBC...

## Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1842 - 317 σελίδες
...Let AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC...

## Elements of geometry: consisting of the first four,and the sixth, books of ...

Euclides - 1842
...AB be the greater ; and from it cut off (3.1.) DB equal to A c, the less, and join D, c : therefore, because in the triangles DBC, ACB, DB is equal to AC, and вc common to both, the two sides, DB, вc are equal to the two A c, c B, each to each ; and the angle...

## The Works of Lord Byron, Τόμος 3

...Concubitu probibere vago ; dare jura maritis ; Oppida moliri ; leges incidere ligno. »idei DB, EC, are equal to the two AC, CB, each to each, and the angle DB( is equal to the angle ACB : therefore, the base DC is equal to the base AB,anri the triangle...

## Euclid in Paragraphs: The Elements of Euclid: Containing the First Six Books ...

Euclid - 1845 - 199 σελίδες
...therefore, because in the triangles DBC, ACB, DB is equal to AC,f and BC common to both, the / \\ t Constr. two sides, DB, BC are equal to the two AC, CB, each to each ; and the angle DBC is equal to the angleJ ACB ; there- ° * t Hyp. fore the base DC is equal to the base AB,...

## The First Six, and the Eleventh and Twelfth Books of Euclid's Elements: With ...

Euclid, James Thomson - 1845 - 352 σελίδες
...other: let AB be the greater, and from it cut oft' (I. 3) BD equal to AC, the less, and join DC. Then, because in the triangles DBC, ACB, DB' is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each; and (hyp.) the angle...

## The Elements of Euclid, the parts read in the University of Cambridge [book ...

Euclides - 1846
...the other. Let AB be the greater; and from it cut off DB equal to AC the less, and join DC : Then, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both triangles, the two sides DB, BC are equal to the two AC, CB, each to each, and the angle...

## Elements of Geometry: Containing the First Six Books of Euclid, with a ...

Euclid, John Playfair - 1846 - 317 σελίδες
...Let AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC...