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" AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... "
Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Σελίδα 13
των Dennis M'Curdy - 1846 - 138 σελίδες
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...proposition of Euclid : " Because, in the triangles DEC, AC B, DB Is equal to AC, and BC common to both ; cy, in iU excursions, could collect ; and, how little fettered he was b angle DBC is equal to the angle ACS: therefore, the base DC is equal to the base AB. and the triangle...

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...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, because in the triangles DBC, ACB, DB is equal to AC, and BC is common to both triangles, also, by supposition, the angle DBC is equal to the angle ACB; therefore, the triangle DBC...

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...let AB be the greater, and from it cut (i. 3.) off DB equal to AC, the less, and join DC.; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each; and the angle DBC is...

The First Two Books of the Elements of Euclid ... with Additional Figures ...

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...AB be the greater; " i'i, '. and from it cut" off DB equal to AC, the less, and join DC; Therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides, DB, BC are equal to the two AC, CB, each to each; and the angle DBC...

The geometry, by T. S. Davies. Conic sections, by Stephen Fenwick

Royal Military Academy, Woolwich - 1853
...; therefore, because in the triangles DBC, ACB, DB is equal to AC (Constr.), and BC common to both, the two sides, DB, BC are equal to the two AC, CB, each to each ; and the angle DBC is equal to the angle (Hyp.) ACB; therefore the base DC is equal to the base AB, and I he...

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...Let AB be the greater, and from it cut off (I. 3.) DB equal to AC, the less, and join DC. Therefore because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, 1. The two sides DB, BC, are equal to the two AC, CB, each to each; and the angle DBC...

The Works of Lord Byron: Embracing His Suppressed Poems, and a Sketch of His ...

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...proposition of Euclid : " Because, In EBB triangles DBC, ACB, DB Is equal to AC, anil EC, common to both ; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DEC ij equal to the angle ACB : therefore, tí» tuse DC Is equal to the base AB, aüd the triangle...

The Works of Lord Byron: Embracing His Suppressed Poems, and a Sketch of His ...

George Gordon Byron Baron Byron - 1854 - 1071 σελίδες
...Euclid : " Became, In S» trungVi DBC, ACB, RB is equal to AC, nnd BC, common to both ; the пим^-tDB, BC, are equal to the two AC, CB, each to each, and the angle Dû: л nfxil to the angle ACB : therefore, the baae DC la equal to the bue A3, ind tb, triangle...

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...greater, and from it cut off DB equal to AC the less, and join CD. Then, because in the triangles DEC, ACB, DB is equal to AC, and BC is common to both triangles, also, by supposition, the angle DBG is equal to the angle ACB ; therefore, the triangle...

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...Then in the triangles DEC, ACB, because DB is assumed to be equal to AC, and BC is common to both, the two sides DB, BC, are equal to the two AC, CB, each to each -, and the angle DBC is equal to the angle ACB ; (hyp.) therefore the base DC must be equal to the base AB, and...




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