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AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle...
Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Σελίδα 13
των Dennis M'Curdy - 1846 - 138 σελίδες
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## Poetical Works, Τόμος 2

...wonder how the devil he came there." The trio are well defined in the sixth proposition of Euclid: "Because, in the triangles DBC, ACB, DB is equal to AC, and BC common to both; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC...

## The Acting Teacher's and Student's in Training Guide and Text Book for ...

Henry Major - 1873
...greater: let AB be the greater- and from it cut off BD equal to AC the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC, are equal to the two AC, CB, each to each; and the angle DBC...

## Pure mathematics, Τόμος 1

Edward Atkins - 1874
...AB, the greater, cut off a part DB, Make equal to AC, the less (I. 3). ' DB=AC. Join DC. PROOF. — Because in the triangles DBC, ACB, DB is equal to...Therefore the two sides DB, BC are equal to the two sides AC, CB, each to each ; And the angle DBC is equal to the angle ACB (Hyp.) Therefore the base...

## Elements of geometry, based on Euclid, books i-iii

Edward Atkins - 1876 - 119 σελίδες
...AB, the greater, cut off a part DB, jiak« equal to AC, the less (I. 3). WJ = AI Join DC. PROOF. — Because in the triangles DBC, ACB, DB is equal to...both, Therefore the two sides DB, BC are equal to the t\vo sides AC, CB, each to each • y\ And the angle DBC is equal to the angle ACB (Hyp.) Therefore...

## Elements of Geometry, Conic Sections, and Plane Trigonometry

Elias Loomis - 1877 - 443 σελίδες
...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, because in the triangles DBC, ACB, DB is equal to AC, and BC is common to both triangles, also, by supposition, the angle DBC is equal to the angle ACB ; therefore the triangle DBC...

## Elements of geometry, based on Euclid, book i

Edward Atkins - 1877
...AC, the less (I. 3). Join DC. PROOF. — Because in the triangles DBC, ACL, DB is equal to AC, and EC is common to both, Therefore the two sides DB, BC are equal to the two sides AC, CB, each to each ; And the angle DBC is equal to the angle ACB (Hyp.) Therefore the base...

## Instruction: a Poem

Isaac Brandon - 1811 - 19 σελίδες
...Becanse, in the triangles DEC, ACB, DB is equal t .i AC, and BC common to both ; the two side* 1) li, BC, are equal to the two AC, CB, each to each, and the angle DBC is equal to the angle ACB : therefore, the base DC is equal to the haee AB, and the triangle...

## Elements of Geometry, Conic Sections, and Plane Trigonometry

Elias Loomis - 1880 - 443 σελίδες
...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, because in the triangles DBC, ACB, DB is equal to AC, and BC is common to botli triangles, also, by supposition, the angle DBC is equal to the angle ACB ; therefore the triangle...

## The questions set at the matriculation examination of the London university ...

Walter Percy Workman - 1880
...and from it cut off DB equal to AC the less, [i. 3 and join DC. Then because in the triangles DEC, ACB, DB is equal to AC, and BC is common to both, the two sides DB, BC are equal to the two sides AC, CB, each to each ; and the angle DBC is equal to...

## Stewart's specific subjects. Euclid. [1st] (-3rd stage). [With 2 issues of ...

Stewart W. and co - 1884
...greater ; let AB be the greater, and from it cut off BD equal to AC the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC, are equal to the two AC, CB, each to each ; and the angle DBC...