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" Divide as in whole numbers, and point off as many figures for decimals in the quotient as the number of decimal places in the dividend exceeds the number in the divisor. "
The Commercial Arithmetic: A Practical Text-book for Business Colleges, High ... - Σελίδα 84
των Warren H. Sadler - 1888
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Complete Graded Arithmetic, Oral and Written: Upon the Inductive Method of ...

James Bates Thomson - 1882 - 416 σελίδες
...decimal places in the dividend exceed those in , -j~7 the divisor, which is one. Hence, the RULE. — Divide as in whole numbers, and from the right of the quotient point off as many figure* for decimals, as the decimal places in the dividend exceed those in the 'divisor. If the quotient...

An Elementary Arithmetic on the Inductive Plan: Including Oral and Written ...

William James Milne - 1882 - 224 σελίδες
...from the number of places in the dividend. (Prin.J RULE. — Divide as if the numbers were integers, and from the right of the quotient point off as many figures for decimals as the number of decimal places in the dividend exceeds those in the divisor. 1. If the...

Second Book in Arithmetic: Comprising Four Years of Oral and Written Work in ...

1882 - 526 σελίδες
...dividend, when necessary, and divide as in integers. II. Point off as many decimal figures in the quotient as the number of decimal places in the dividend exceeds the number in the divisor. a. Count decimal ciphers annexed to form a partial dividend, as decimal places of the...

A New Complete Arithmetic: Uniting Oral and Written Exercises

Emerson Elbridge White - 1883 - 374 σελίδες
...Rule. — Divide as in the division of integers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor. NOTES. — 1. When the divisor and dividend contain the same number of decimal places,...

The universal instructor, or, Self-culture for all, Τόμος 2

Ward, Lock and co, ltd - 1884 - 958 σελίδες
...inclndes all three rules. To find the gnat i< nt to any number of dtrimal flacf*. — See that tiie number of decimal places in the dividend exceeds the number of decimal places in the divisor by at least as many decimal places as we wish the quotient tQ have. (This is effected by annexing ciphers,...

Advanced Arithmetic for Secondary Schools: A Comprehensive Treatise on the ...

John Homer French - 1889 - 512 σελίδες
...and to obtain the decimal part of the quotient, there must be as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor (2C7, III, 3). Therefore, I first annex decimal ciphers to the dividend when necessary,...

Complete Arithmetic: Combining Oral and Written Exercises

Edward Sylvester Ellis - 1889 - 370 σελίδες
...Division of Decimals. — Divide as in whole numbers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor. NOTE. — When the dividend has fewer decimal places than the divisor, annex enough...

First Book of Arithmetic: Uniting Oral and Written Exercises

Emerson Elbridge White - 1890 - 178 σελίδες
...RULE. — Divide as in the division of integers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor. NOTES. — 1. When the divisor contains more decimal places than the dividend, annex...

Teachers Magazine, Τόμος 36

1913 - 456 σελίδες
...Since .275 = 2751000, and .05 = 5-100, 275-1000 -r5-100 = 275-1000 X 100-5 = 55-10 = 5.5. Thus, we divide as in whole numbers, and from the right of the quotient point off as many places as the number of decimal places in the dividend exceeds the number in the divisor. Find the...

Intermediate Book

William Seneca Sutton - 1892 - 144 σελίδες
...decimals by decimals : Divide as in whole numbers. Point off in the quotient as many decimal places as the number of decimal places in the dividend exceeds the number of decimal places in the divisor, prefixing noughts when necessary. 18. Divide the product of 10.90 and .32 by the product of 5.45 and...




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