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" Find the value of one of the unknown quantities, in terms of the other and known quantities... "
An Elementary Treatise on Algebra: Theoretical and Practical ... - Σελίδα 146
των James Ryan - 1826 - 383 σελίδες
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First B.A. Examination, University of London: A Hand-book to the Study of ...

J. G - 1878 - 372 σελίδες
...789 i By subtraction 153y = 459, or y = 3, and.'.z = 2. The method which depends upon substituting the value of one of the unknown quantities in terms of the other, may be used witli advantage whenever either of the unknown quantities, x or y, has a coefficient unity...

Elementary algebra: with brief notices of its history

Robert Potts - 1879
...may be determined from these equations, a¡x+bly = ol, a¿c+b¿y = cíl. First method : By finding the value of one of the unknown quantities in terms of the other and known quantities, from one equatiou, and substituting it in the other equation. Let the value of x be found from the...

Elementary algebra, with brief notices of its history

Robert Potts - 1879
...bo determined from these equations, a1z-\-bty = cl, а^с-\-1>^у = сг. First method : By finding the value of one of the unknown quantities in terms of the other and known quantities, from one equation, and substituting it in the other equation. Let the value of x be found from the...

Algebra

C R. Lupton - 1879
...2y = 26, /. Зж + 8 = 26 ; transposing, Зж =18, .'. ж = 6. SECOND METHOD. 82. By Substitution. —Find the value of one of the unknown quantities in terms of the other from either equation, and substitute this value in the other equation. Taking the same equation as...

University Algebra

Webster Wells - 1879 - 444 σελίδες
...uniting terms, 41 x = 82 Whence, ж =2. Substituting this value in (3), у = — - — = — 3. BULE. Find the value of one of the unknown quantities in terms of the other, from either of the given equations * and substitute this value for that quantity in the other equation....

An Easy Algebra for Beginners: Being a Simple, Plain Presentation of the ...

Charles Scott Venable - 1880 - 157 σελίδες
...equation. For this case we have the Rule. — From the equation of the first degree find the expression of one of the unknown quantities in terms of the other, and then substitute this expression in the second equation. Ex. 1. Given x 4 y = 10 (1) Ь0 find the values...

Elements of Algebra

George Albert Wentworth - 1881 - 384 σελίδες
...11, .-. x=l. 191. Hence, to eliminate an unknown quantity by comparison, from each equation obtain the value of one of the unknown quantities in terms of the other. Form an equation from these equal values and reduce the equation. NOTE. If, in the last example, (3)...

The student's algebra

James Mackean - 1881
...that may be employed. 158. I. When one of the equations is simple. Find from the simple equation a value of one of the unknown quantities in terms of the other, and substitute this value in the other equation. Illustrative Example. From [2], x = 2y + 3. Substitute...

A School Algebra

Simon Newcomb - 1882 - 279 σελίδες
...— ?— = — ^— ; 2ж + « = 30. 8 — у 4 — ж' ' -; Elimination by Substitution. 159. RULE. Find the value of one of the unknown quantities in terms of the other from one equation, and substitute this value in the other equation. The latter will then have but one...

A Complete Course in Algebra for Academies and High Schools

Webster Wells - 1885 - 349 σελίδες
...132 = — 124 -ж= 8 Whence, a; = — 8 Substituting this value in (3) , у = ~40+44 _ 2 ¿à BULB. Find the value of one of the unknown quantities in terms of the other from one of the given equations, and substitute this value for thai quantity in the other equation....




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