 | William Freeland - 1895 - 328 σελίδες
...5. ... y = l. Substitute in (1), x + 3 = 27. .-. ж = 13. 182. Hence, to eliminate by comparison : Find the value of one of the unknown quantities in terms of the other in each equation ; make a new equation from the equal vulues thus obtained. From this new equation... | |
 | Webster Wells - 1897 - 522 σελίδες
...Substituting the value of x in (3), у = — — ^ — = — 4 EULE. From one of the given equations find the value of one of the unknown quantities in terms of the other, and substitute this value in place of that quantity in the other equation. / 10. { EXAMPLES. Solve by the... | |
 | Fletcher Durell, Edward Rutledge Robbins - 1897 - 482 σελίδες
...Substitute for у in (3), x = 36 ~ 26 = 2 о Hence, in general, Jn one о/ ¿Ле given equations obtain the value of one of the unknown quantities in terms of the other unknown quantity ; Substitute this value in the other equation and solve. EXERCISE 56. Solve by substitution.... | |
 | Webster Wells - 1897 - 422 σελίδες
...second dey гее. and the other of the first. Equations of this kind may always be solved by finding the value of one of the unknown quantities in terms of the other from the simple equation, and substituting this value in the other equation. 1. Solve the equations... | |
 | Webster Wells - 1904 - 384 σελίδες
...the second degree, and the other of the first. Equations of this kind may always be solved by finding the value of one of the unknown quantities in terms of the other from the simple equation, and substituting this value in the other equation. 1. Solve the equations... | |
 | International Correspondence Schools - 1897 - 672 σελίδες
...(8), _1+2X4 ~~3 ; whence, .* = 3. Ans. 61O. To Eliminate by Comparison : Rule. — From cadi equation find the value of one of the unknown quantities in terms of the oilier. Form a new equation by placing tliese two values equal to each other and solve. Elimination... | |
 | Webster Wells - 1897 - 386 σελίδες
...the second degree, and the other of the first, Equations of this kind may always be solved by finding the value of one of the unknown quantities in terms of the other from the simple equation, and substituting this value in the other equation. 1. Solve the equations... | |
 | International Correspondence Schools - 1899 - 722 σελίδες
...in equation (8), whence, x = 3. Ans. 61O. To Eliminate by Comparison : Rule. — From each equation find the value of one of the unknown quantities in terms of the other. Form a new equation by placing these two -values equal to each other and solve. Elimination by comparison... | |
 | Louis Parker Jocelyn - 1902 - 460 σελίδες
...therefore, always possible. 441. PROBLEM 1. To solve equations under Prop. 1. Rule. From the linear equation find the value of one of the unknown quantities in terms of the other unknown quantity and the known quantities. Substitute this value in the quadratic equation, and solve... | |
 | William Kent - 1902 - 1204 σελίδες
...first equation, Zx + 3 = 7; x = 2. Elimination by substitution. — From one of the equations obtain the value of one of the unknown quantities in terms of the other. Substitutute for this unknown quantity its value in the other equation and reduce the resulting equations.... | |
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Find the value of one of the unknown quantities, in terms of the other and known quantities... 
