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" Find the value of one of the unknown quantities, in terms of the other and known quantities... "
An Elementary Treatise on Algebra: Theoretical and Practical ... - Σελίδα 146
των James Ryan - 1826 - 383 σελίδες
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Algebra for Schools and Colleges

William Freeland - 1895 - 309 σελίδες
...5. ... y = l. Substitute in (1), x + 3 = 27. .-. ж = 13. 182. Hence, to eliminate by comparison : Find the value of one of the unknown quantities in terms of the other in each equation ; make a new equation from the equal vulues thus obtained. From this new equation...

Essentials of Algebra for Secondary Schools

Webster Wells - 1897 - 411 σελίδες
...Substituting the value of x in (3), у = — — ^ — = — 4 EULE. From one of the given equations find the value of one of the unknown quantities in terms of the other, and substitute this value in place of that quantity in the other equation. / 10. { EXAMPLES. Solve by the...

The Elements of Mechanical Engineering, Τόμος 1

International Correspondence Schools - 1897
...(8), _1+2X4 ~~3 ; whence, .* = 3. Ans. 61O. To Eliminate by Comparison : Rule. — From cadi equation find the value of one of the unknown quantities in terms of the oilier. Form a new equation by placing tliese two values equal to each other and solve. Elimination...

Essentials of Algebra

Webster Wells - 1897 - 358 σελίδες
...second dey гее. and the other of the first. Equations of this kind may always be solved by finding the value of one of the unknown quantities in terms of the other from the simple equation, and substituting this value in the other equation. 1. Solve the equations...

Essentials of Algebra for Secondary Schools

Webster Wells - 1904 - 367 σελίδες
...the second degree, and the other of the first. Equations of this kind may always be solved by finding the value of one of the unknown quantities in terms of the other from the simple equation, and substituting this value in the other equation. 1. Solve the equations...

A School Algebra Complete

Fletcher Durell, Edward Rutledge Robbins - 1897 - 436 σελίδες
...Substitute for у in (3), x = 36 ~ 26 = 2 о Hence, in general, Jn one о/ ¿Ле given equations obtain the value of one of the unknown quantities in terms of the other unknown quantity ; Substitute this value in the other equation and solve. EXERCISE 56. Solve by substitution....

Essentials of Algebra for Secondary Schools

Webster Wells - 1897 - 411 σελίδες
...the second degree, and the other of the first, Equations of this kind may always be solved by finding the value of one of the unknown quantities in terms of the other from the simple equation, and substituting this value in the other equation. 1. Solve the equations...

Arithmetic, algebra, logarithms, geometry and trigonometry, elementary ...

International Correspondence Schools - 1899
...in equation (8), whence, x = 3. Ans. 61O. To Eliminate by Comparison : Rule. — From each equation find the value of one of the unknown quantities in terms of the other. Form a new equation by placing these two -values equal to each other and solve. Elimination by comparison...

An Algebra for High Schools and Academies

Louis Parker Jocelyn - 1902 - 445 σελίδες
...therefore, always possible. 441. PROBLEM 1. To solve equations under Prop. 1. Rule. From the linear equation find the value of one of the unknown quantities in terms of the other unknown quantity and the known quantities. Substitute this value in the quadratic equation, and solve...

The Mechanical Engineer's Pocket-book: A Reference Book of Rules, Tables ...

William Kent - 1902 - 1113 σελίδες
...first equation, Zx + 3 = 7; x = 2. Elimination by substitution. — From one of the equations obtain the value of one of the unknown quantities in terms of the other. Substitutute for this unknown quantity its value in the other equation and reduce the resulting equations....




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