 | J. G - 1878 - 408 σελίδες
...789 i By subtraction 153y = 459, or y = 3, and.'.z = 2. The method which depends upon substituting the value of one of the unknown quantities in terms of the other, may be used witli advantage whenever either of the unknown quantities, x or y, has a coefficient unity... | |
 | Robert Potts - 1879 - 672 σελίδες
...may be determined from these equations, a¡x+bly = ol, a¿c+b¿y = cíl. First method : By finding the value of one of the unknown quantities in terms of the other and known quantities, from one equatiou, and substituting it in the other equation. Let the value of x be found from the... | |
 | Robert Potts - 1879 - 668 σελίδες
...bo determined from these equations, a1z-\-bty = cl, а^с-\-1>^у = сг. First method : By finding the value of one of the unknown quantities in terms of the other and known quantities, from one equation, and substituting it in the other equation. Let the value of x be found from the... | |
 | C R. Lupton - 1879 - 194 σελίδες
...2y = 26, /. Зж + 8 = 26 ; transposing, Зж =18, .'. ж = 6. SECOND METHOD. 82. By Substitution. —Find the value of one of the unknown quantities in terms of the other from either equation, and substitute this value in the other equation. Taking the same equation as... | |
 | Webster Wells - 1879 - 468 σελίδες
...uniting terms, 41 x = 82 Whence, ж =2. Substituting this value in (3), у = — - — = — 3. BULE. Find the value of one of the unknown quantities in terms of the other, from either of the given equations * and substitute this value for that quantity in the other equation.... | |
 | Charles Scott Venable - 1880 - 168 σελίδες
...equation. For this case we have the Rule. — From the equation of the first degree find the expression of one of the unknown quantities in terms of the other, and then substitute this expression in the second equation. Ex. 1. Given x 4 y = 10 (1) Ь0 find the values... | |
 | James Mackean - 1881 - 510 σελίδες
...that may be employed. 158. I. When one of the equations is simple. Find from the simple equation a value of one of the unknown quantities in terms of the other, and substitute this value in the other equation. Illustrative Example. From [2], x = 2y + 3. Substitute... | |
 | George Albert Wentworth - 1881 - 400 σελίδες
...11, .-. x=l. 191. Hence, to eliminate an unknown quantity by comparison, from each equation obtain the value of one of the unknown quantities in terms of the other. Form an equation from these equal values and reduce the equation. NOTE. If, in the last example, (3)... | |
 | Simon Newcomb - 1882 - 302 σελίδες
...— ?— = — ^— ; 2ж + « = 30. 8 — у 4 — ж' ' -; Elimination by Substitution. 159. RULE. Find the value of one of the unknown quantities in terms of the other from one equation, and substitute this value in the other equation. The latter will then have but one... | |
 | Webster Wells - 1885 - 372 σελίδες
...132 = — 124 -ж= 8 Whence, a; = — 8 Substituting this value in (3) , у = ~40+44 _ 2 ¿à BULB. Find the value of one of the unknown quantities in terms of the other from one of the given equations, and substitute this value for thai quantity in the other equation.... | |
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Find the value of one of the unknown quantities, in terms of the other and known quantities... 
