 | Euclides - 1846 - 292 σελίδες
...equal to the rectangle BE, ED. But let one of them, BD, pass through the centre, and cut the other AC, which does not pass through the centre, at right angles, in the point E : Bisect BD in F, which must be the centre of the circle ABCD, and join AF : Then, because BD, which... | |
 | Euclid, Thomas Tate - 1849 - 120 σελίδες
...equal to the rectangle BE, ED. But let one of them BD pass through the centre, and cut the other AC, which does not pass through the centre, at right angles, in the point E : Then, if BD be bisected in F, F is the centre of the circle ABCD ; join AF : And because BD, which passes... | |
 | Euclides - 1853 - 176 σελίδες
...equal to the rectangle be, e d. But let one of them bd pass through the centre, and cut the other a С which does not pass through the centre, at right angles, in the point e : then, if bd be bisected in f, f is the centre of the circle ab С d ; join af And because bd, which passes... | |
 | Euclides - 1853 - 146 σελίδες
...equal to the rectangle BE, ED. But let one of them BD pass through the centre, and cut the other AC, which does not pass through the centre, at right angles, in the point liL Then if BD be bisected in F, Fis the centre of the circle ABCD. Join AF. And because BD, which... | |
 | Euclides - 1855 - 270 σελίδες
...equal to the rectangle BD.ED. Secondly, let the one BD pass through the centre, and cut the other A С, which does not pass through the centre, at right angles, in the' point E. Find F, the centre of the circle AB СD, and join AF. Because BD passing through the centre, cuts the... | |
 | Euclides - 1860 - 288 σελίδες
...rectangle BE • ED. Case Second. — But let one of them BD pass through the centre, and cut the other AC, which does not pass through the centre, at right angles, in the point E ; then if BD be bisected in F, F is the centre of the circle ABCD ; join AF ; (De;n.) and because BD, which... | |
 | Euclides - 1862 - 172 σελίδες
...because E is the centre, Secondlu, let one of them BD pass through the centre, and cat the other AC, which does not pass through the centre, at right angles in the point E. CONSTRUCTION Then if BD be bisected in F, F is the centre of the circle ABCD. Join AF. DEMONSTRATION... | |
 | Euclides - 1863 - 122 σελίδες
...ED are all equal (LDef. 15) Secondly, let the one BD pass through the centre, and cut the other AC, which does not pass through the centre, at right angles, in the point E. Therefore the rectangle AE.EC, is equal to the rectangle BD.ED. Find F, the centreof the circle ABCD,... | |
 | Euclides - 1865 - 402 σελίδες
...to the rectangle BE, ED. Secondly, let one of them BD pass through the centre, and cut the other AC, which does not pass through the centre, at right angles in the point E. CONSTRUCTION Then if BD be bisected in F, F is the centre of the circle ABCD. Join AF. DEMONSTRATION... | |
 | Edward Atkins - 1874 - 426 σελίδες
...rectangle BE, ED. CASE II. — Let one of them, BD, pass through the centre, and cut the other, AC, which does not pass through the centre, at right angles, in the point E. CONSTRUCTION. — Bisect BD in F, then F is the centre of the circle; join AF. PROOF. — Because BD,... | |
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But let one of them BD pass through the centre, and cut the other AC, which does not pass through the centre, at right angles, in the... 
