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" To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content. "
Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ... - Σελίδα 204
των Nathan Daboll - 1831 - 240 σελίδες
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Arithmetic. [With] Key, Τόμος 1

Robert Goodacre - 1839
...Example 1 29 Miscellaneous Questions. CASE 1. — To find the area of any rectangular superficies. Multiply the length by the breadth, and the product will be the area in square measure. In measuring superficies, in which the dimensions vary, it is common to take the...

The Western Calculator, Or, A New and Compendious System of Practical ...

Joseph Stockton - 1839 - 203 σελίδες
...32J perches. 3<2. To find the content of an oblong square piece of ground, called a parallelogram. RULE. Multiply the length by the breadth, and the product will be the answer. EXAMPLE. i 1. There is an oblong square piece of ground, A, B, C, D, the longest sides of which...

First Lessons in Geometry: With Practical Applications in Mensuration, and ...

Charles Davies - 1840 - 252 σελίδες
...the more accurate methods by means of figures. PROBLEM I. 2. To find the area of a board or plank. RULE. Multiply the length by the breadth, and the product •will be the content required. Of Timber Measure. NOTE. — 3. If the board is tapering, add the breadths of the...

Ruger's Arithmetick, with Questions and Answers: A New System of Arithmetick ...

William Ruger - 1841 - 263 σελίδες
...a square lot eontain, measuring 40 rods on each side ? Ans. 10 acres. 24 feet. To find the area of a parallelogram, or long square. RULE. — Multiply the length by the breadth, and the product will ea, or superficial content, in the same name with the length be the area, of the sides. 100 rods. EXAMPLES....

Adams's New Arithmetic...: Arithmetic, in which the Principles of Operating ...

Daniel Adams - 1848 - 306 σελίδες
...multiply the number of squares in one row by the number of rows ; 5X3=15 square rods, Ans. Hence the RULE. Multiply the length by the breadth, and the product will be the square contents. NOTE. — Three times a line 5 rods long is a line 15 rods long. Hence the pupil must...

Schoolmaster's Assistant: Improved and Enlarged, Being a Plain Practical ...

Nathan Daboll - 1843
...— 160 square rods make an acre. Therefore, 26x^6=676 sq. rods. and 676-i-l60=4« 36r. the dnswer. ART. 2. To measure a parallelogram, or long square....A certain garden, in form of a long square, is 96 ft. .ong, and 54 wide; how many square feet of ground are contained in it ? Jlnt. 96x54=5144 square...

Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1843 - 240 σελίδες
...make an acre. Therefore, 2бхзаб=СГ6 sq. rods, and 6Г6ч-1бО=4в 36r. the Answer. Ант. 2. To measure a parallelogram, or long square. RULE....area, or superficial content. EXAMPLES. 1. A certain carden, in form of a long square, is 96 ft. ong, and 54 wide ; InJw many square feet of ground are...

Daboll's Complete Schoolmaster's Assistant Being a Plain Comprehensive ...

Nathan Daboll - 1843 - 240 σελίδες
...whole number of square rods to acres.] Ans. 26 acres I r. 25 rods. PROB. ii. — To find the area of a parallelogram, or long square. RULE. Multiply the...by the breadth, and the product will be the area. EXAMPLES. 1. How many square yards of ground are contained in a garden which is 126 feet long and 65...

Watson's Tutor's assistant; or, Complete school arithmetic

William WATSON (of Beverley.) - 1845 - 12 σελίδες
...MENSURATION OF SURFACES. PROBLEM 1. — To find the area of a square, rectangle, parallelogram, SfC. * RULE. — Multiply the length by the breadth, and the product will be the area, or multiply half the sum of the parallel sides by their perpendicular distance. EXAMPLES. 1. What is the...

The Columbian Calculator; Being a Practical and Concise System of Decimal ...

Almon Ticknor - 1846 - 264 σελίδες
...sides are perpendicular to each other (right-angled), but the adjacent sides are longer and parallel. RULE. Multiply the length by the breadth, and the product will be the answer. 1 . A garden is 76 feet in length, and 42 feet in width ; how many square feet of ground are...




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