 | Benjamin Greenleaf - 1864 - 420 σελίδες
...left-hand period, and place its root on the right ; subtract the square of this root from the first period, and to the remainder bring down the next period for a dividend. Divide this quantity, omitting the last figure, by double the part of the root already found, and annex... | |
 | George Augustus Walton - 1864 - 364 σελίδες
...period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
 | George Augustus Walton - 1864 - 376 σελίδες
...period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor. Divide... | |
 | Joseph Ray - 1866 - 252 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times the divisor... | |
 | Joseph Ray - 1866 - 250 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times the divisor... | |
 | Horatio Nelson Robinson - 1866 - 328 σελίδες
...for the first figure in the required root ; subtract the square of this figure from the first period, and to the remainder bring down the -next period for a dividend. III. Double the root already found, and write the result on the left for a divisor ; find how many... | |
 | Joseph Ray - 1852 - 422 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. Srd. Double the root already found, and place it on the left for a divisor. Find how many times the... | |
 | Joseph Ray - 1866 - 420 σελίδες
...and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
 | Robert Thomson (of Southampton.) - 1866 - 180 σελίδες
...number : cube this figure placed in the quotient and place its product under the first period, subtract and to the remainder bring down the next period for a dividend. Example 1st. — Extract the cube or third root of 312908547060. 6x6=36 6x3=18x6= 10800 187x7= 1309... | |
 | Ezra S. Winslow - 1867 - 232 σελίδες
...period, and place its root in the quotient; subtract the square of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Multiply the root so far found — the figure in the quotient — by 2, for a divisor ; see how... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
