 | Oscar F. Williams - 1894 - 364 σελίδες
...right of the divisor; multiply the divisor thus formed by the new root figure, subtract the result from the dividend, and to the remainder bring down the next period, and so proceed till the last period has been brought down, considering the entire root already found... | |
 | Horatio Nelson Robinson - 1895 - 526 σελίδες
...complete divisor ; multiply the complete divisor by the trial term in the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. To the last complete divisor add the last term of the root, and to the sum annex one cipher, for... | |
 | Joseph Ray - 1903 - 366 σελίδες
...complete divisor. 5. Multiply the complete divisor by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Find a new trial divisor as before, and continue the operation in the same manner until all the... | |
 | Calvin Franklin Swingle, Frederick John Prior - 1906 - 676 σελίδες
...the dividend, and it will be the second figure of the root. From the dividend subtract the product, and to the remainder bring down the next period for a new dividend. Double the figures in the quotient for a divisor, and continue the operation as above till all the... | |
 | Henry Adams - 1907 - 594 σελίδες
...in the root; add these three last found numbers together, and subtract this sum from the dividend ; to the remainder bring down the next period for a new dividend, and proceed as before. . Example.—Required the cube root of 444194947. 444194947(763 343 7 X 7 X... | |
 | Stephen Roper - 1907 - 878 σελίδες
...the true divisor, which multiply by the last root figure and subtract th« product from the dividend. To the remainder bring down the next period for a new dividend. Continue the operation until all of the periods have been brought down. NOTE. — If a dividend does... | |
 | Andrew Cassius West - 1909 - 282 σελίδες
...for the true divisor, multiply by the last root figure, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new trial divisor, and continue the operation as before until all... | |
 | Jennings Cropper Wise - 1912 - 352 σελίδες
...to the root and to the divisor; multiply the completed divisor by the quotient, subtract the product from the dividend, and to the remainder bring down the next period as before. Double the whole root found for a new trial divisor, and proceed as before until all the... | |
 | Frank Eugene Kidder - 1921 - 1944 σελίδες
...divisor. Multiply this final divisor by the number in the quotient just found, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend and proceed as before. If it should be found that the trial divisor cannot be contained in the dividend,... | |
 | Frank Eugene Kidder - 1921 - 1950 σελίδες
...left-hand period, and place its root in the quotient; subtract the said square from the left-hand period, and to the remainder bring down the next period for a new dividend. (3) Double the root already found, and annex one cipher for a trial-divisor; lee how тану times... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
