 | Elias Loomis - 1864 - 386 σελίδες
...square of the second figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found... | |
 | Horatio Nelson Robinson - 1864 - 444 σελίδες
...result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a, new dividend. VI. Add together the last complete divisor, the last correction,... | |
 | Robert Thomson (of Southampton.) - 1866 - 180 σελίδες
...quotient and also in the unit's place of the divisor. Fifth. — Multiply this divisor by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next point for a new dividend, double the last figure set in the divisor and proceed as before... | |
 | Joseph Ray - 1852 - 422 σελίδες
...sum will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. Extract... | |
 | Joseph Ray - 1866 - 420 σελίδες
...sum will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods arc brought down. Extract... | |
 | Joseph Ray - 1866 - 250 σελίδες
...the right of the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue... | |
 | Horatio Nelson Robinson - 1866 - 328 σελίδες
...result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
 | Ezra S. Winslow - 1867 - 232 σελίδες
...and to the light of the divisor, as before ; multiply the divisor, as it now stands, by the figure last placed in the quotient, and subtract the product...from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by... | |
 | Robert Wallace - 1870 - 164 σελίδες
...of the partial divisor. Multiply the complete divisor by the last figure of the root thus obtained, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the whole root already found for a partial divisor, and... | |
 | Ezra S. Winslow - 1872 - 256 σελίδες
...and to the right of the divisor, as before ; multiply the divisor, as it now stands, by the figure last placed in the quotient, and subtract the product...from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
