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" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
Conkling's Arithmetic: The Young Arithmetician's Guide to a Knowledge of ... - Σελίδα 109
των Thomas Conkling (W.) - 1831 - 275 σελίδες
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The Common School Arithmetic ...: To which is Added a Dictionary of ...

Peirpont Edward Bates Botham - 1837 - 252 σελίδες
...question. The first and third terms must be of one name. The second term of -divers denominations. Multiply the second and third terms together, and...divide the product by the first term ; the quotient thence arising will be the Answer. OBS. This rule is founded on the obvious principle, that the magnitude...

A System of Geometry and Trigonometry, with a Treatise on Surveying: In ...

Abel Flint - 1837 - 338 σελίδες
...is calculated accordingly. GENERAL ROLE. 1. State the question in every case, as already taught : 2. Multiply the second and third terms together, and divide the product by the first. The manner of taking natural sines and tangents from the tables, is the same as for logarithmic sines...

A complete treatise on practical land-surveying

Thomas Holliday - 1838 - 404 σελίδες
...3.—By arithmetical computation. Having stated the question according to the proper rule or case, multiply the second and third terms together and divide the product by the first, and the quotient will be the fourth term required for the natural number. But in working by logarithms,...

The parent's guide to a liberal ... education; containing a selection of ...

Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 σελίδες
...When the terms are stated and reduced, how do you proceed in order to find a fourth proportional? I multiply the second and third terms together, and divide the product by the first, the quotient is the answer. In what name are the product of the second and third terms, the quotient,...

A Practical and Theoretical System of Arithmetic: Containing a New System of ...

George Willson - 1838 - 194 σελίδες
...mentioned in it.* * It is often better to reduce the lower denominations to tha daeimil «f the highest 3. Multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in that denomination which the third term was bft in. In arranging...

The North American Arithmetic: For Advanced Scholars. part third

Frederick Emerson - 1839 - 300 σελίδες
...the fourth, make the less of the two remaining terms the Jirst term, and the greater the second: then multiply the second and third terms together, and...product by the first term: the quotient will be the fourth. term, or answer. 1. If I buy 871 yards of cotton cloth for 78 dollars 39 cents, what is the...

Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of ...

Nathan Daboll - 1839 - 220 σελίδες
...the least of the two remaining numbers for the second term, and the greater for the first term ; then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer in the same name of the third term. EXAMPLES. 1. If 6 yards cost...

The Western Calculator, Or, A New and Compendious System of Practical ...

Joseph Stockton - 1839 - 218 σελίδες
...the first, but if less place the greater for the first term, and the remaining one for the second. Multiply the second and third terms together, and divide the product by the first ; the quotient will be the answer required. EXAMPLES. 1. If 30 horses plow 12 acres, how many will...

The Private Instructor, Or Mathematics Simplified: Comprising Every Thing ...

Jason M. Mahan - 1839 - 312 σελίδες
...denomination, reduce both to the lowest in either, and the third to its lowest denomination mentioned. Multiply the second and third terms together, and divide the product by the first : the quotient will be the answer to the question, in the same denomination you left the third term...

Arithmetic. [With] Key, Τόμος 1

Robert Goodacre - 1839 - 320 σελίδες
...multiply all those which are not marked for a general dividend. Divide the dividend by the divisor : the quotient will be the answer to the question in the same denomination as the middle term was left in when it was multiplied with the others. Example worked....




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