... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... A Treatise on Arithmetic - Σελίδα 329των J. Brookes - 1776 - 346 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
| James Gray - 1854 - 120 σελίδες
...root of that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide the dividend... | |
| Benjamin Greenleaf - 1854 - 342 σελίδες
...for the first figure of the root, and the square number under the period, subtracting it therefrom ; and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor, 4. Find... | |
| Horatio Nelson Robinson - 1854 - 306 σελίδες
...period, and set its root on the right of the given number; subtract said square from the left-hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and fry how often this divisor (with the figure used in... | |
| Roswell Chamberlain Smith - 1856 - 334 σελίδες
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,... | |
| Charles Guilford Burnham - 1857 - 328 σελίδες
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the, quotient by... | |
| Joseph Ray - 1857 - 348 σελίδες
...its root on the right. like a quotient in division. Subtract the square of this root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the .root found, and place it on the left for a trial divisor. Find how many times the divisor... | |
| Benjamin Greenleaf - 1857 - 336 σελίδες
...the left-hand period, and place its root on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend, and... | |
| Charles Guilford Burnham - 1857 - 342 σελίδες
...quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the... | |
| Joseph Ray - 1857 - 408 σελίδες
...right, after the manner of a quotient in division. Subtract the square of the root from the left per'od, and to the remainder bring down the next period for a dividend. 3rd. Double the root already found, and place it on the left for a divisor. Find how many times the... | |
| Benjamin Greenleaf - 1857 - 452 σελίδες
...period, and write its root as the first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor,... | |
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