| Frank Hickenlooper - 1896 - 384 σελίδες
...cross-wise, and if the errors were alike — that is, both greater or less than the given number — divide the difference of the products by the difference of the errors, and the quotient was the answer ; but if the errors were unlike, the sum of the products should be divided... | |
| Frank Hickenlooper - 1896 - 380 σελίδες
...cross-wise, and if the errors were alike — that is, both greater or less than the given number — divide the difference of the products by the difference of the errors, and the quotient was the answer ; but if the errors were unlike, the sum of the products should be divided... | |
| 1900 - 654 σελίδες
...positions by their alternate errors, and if the errors are alike, that is, both excesses or both defects, divide the difference of the products by the difference of the errors ; but if the errors are not alike, divide the sum of the products by the sum of the errors, and the... | |
| John Charles Stone - 1926 - 344 σελίδες
...supposition by the first error. 4. // the errors be alike (that is, both too small or both too great), divide the difference of the products by the difference of the errors and the quotient will be the answer. 5. // the errors be unlike (one too large and one too small), divide the... | |
| Nathan Daboll - 1825 - 258 σελίδες
...3. Multiply the first position by the last error, and tbt last position by the first error. 4. It' the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer. 5. If the errors are unlike, divide the sum of the products by the sum... | |
| 1901 - 562 σελίδες
...position by the first error. 4. If the errors be alike, that is, both too small or both too great, divide the difference of the products by the difference of the errors, and the quotient will be the answer. 5. If the errors be unlike, divide the sum of the products by the sum... | |
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