 | Charles Guilford Burnham - 1857 - 328 σελίδες
...the square of the last quotient figure, and place this product tinder the last ; under these write the cube of the last quotient figure, and call their...remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Benjamin Greenleaf - 1857 - 452 σελίδες
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. To the last true divisor and the number immediately over it, add the square of the last root figure,... | |
 | Charles Guilford Burnham - 1857 - 342 σελίδες
...cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from tlte dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Joseph Ray - 1857 - 348 σελίδες
...Multiply the complete dicisor by the last figure of the root, and subtract the product from the dividend; to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. NOTES. — 1. When the product of the complete... | |
 | Benjamin Greenleaf - 1857 - 336 σελίδες
...figure last annexed by the figure annexed to the root, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new divisor, and continue the operation as before, till all the... | |
 | Daniel Adams - 1858 - 354 σελίδες
...obtained, together with the cube of the last quotient, to the former product for a subtrahend. VII. Subtract the subtrahend from the dividend, and to...remainder bring down the next period for a new dividend, vith which proceed as before, till the work is finished. NOTE 1 . — If it happens that the divisor... | |
 | Elias Loomis - 1858 - 394 σελίδες
...figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
 | Benjamin Greenleaf - 1858 - 472 σελίδες
...for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the product annex two ciphers for... | |
 | Thomas William Silloway - 1858 - 236 σελίδες
...the right hand of the divisor. Multiply the divisor by the last quotient-figure, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, 4th, Double the quotient already found for a partial divisor, and from these find the next figure in... | |
 | Charles Haynes Haswell - 1858 - 350 σελίδες
...period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor is contained... | |
| |
Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
